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2 years ago

The general form for a linear equation is given as: y = a + bx. In the regression equation, b is called the ______.

Mathematics

1 answer:

Viktor [21]2 years ago

5 0

Answer:

Slope

Step-by-step explanation:

In the regression equation y=a+bx, y is dependent variable and x is independent variable. It means that due to change in x the y changes respectively. The "a" is intercept of the model and it shows the value of y when x is zero. The "b" is the slope of the model and it depicts the change in y due to unit change in x. The positive value of b means that as the x increases y also increases and as the x decreases y also decreases. The negative value of b means that as the x decreases y increases and as the x increases the y decreases.The sign of b shows the type of relationship between independent and dependent variable.

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.

const2013 [10]

Answer:

$T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

Step-by-step explanation:

Remember that for any curve $r(t)$

The tangent vector is given by

$T(t) = \frac{r'(t) }{| r'(t)| }$

And the normal vector is given by

$N(t) = \frac{T'(t)}{|T'(t)|}$

For this case, using the chain rule

$r'(t) = ( -10*2tsin(t^2) , 102t cos(t^2) )\\$

And also remember that

$|r'(t)| = \sqrt{(-10*2tsin(t^2))^2 + ( 10*2t cos(t^2) )^2} \\\\ = \sqrt{400 t^2*( sin(t^2)^2 + cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t$

Therefore

$T(t) = r'(t) / |r'(t) | = ( -10*2tsin(t^2) , 10*2t cos(t^2) )/ 20t\\\\ = ( -10*2tsin(t^2)/ 20t , 10*2t cos(t^2) / 20t )\\= ( -sin(t^2), cos(t^2) )$

Similarly, using the quotient rule and the chain rule

$T'(t) = ( -2t cos(t^2) , -2t sin(t^2))$

And also

$|T'(t)| = \sqrt{ ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t$

Therefore

$N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

Notice that

1. $|N(t)| = |T(t) | = \sqrt{ cos(t^2)^2 + sin(t^2)^2 } = \sqrt{1} = 1$

2. $N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0$

Simlarly

$r'(t) = (2t,-6,0) \\$

and

$|r'(t)| = \sqrt{(2t)^2 + 6^2} = \sqrt{4t^2 + 36}$

Therefore

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

Then

$T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)$

and also

$|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 + ( (3 t)/(9 + t^2)^{3/2})^2 + 0^2 }\\= 3/(t^2 + 9 )$

And since

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

6 0

2 years ago

Find area PLEASE PLEASE PLEASE

yan [13]

Answer: 39.22 yd^2 (as in yards squared)

Step-by-step explanation:

1. DO NOT FOCUS ON THE 6! JUST FOCUS ON THE BASE AND HEIGHT!

2. Area= b*h

3. Plus in your numbers. Area=3.7*10.6.

4. Multiply. Area=39.22 yds^2

4 0

2 years ago

About how heavy is an adult camel?

pentagon [3]

Answer:

they range from 800 to 1300 pounds, depending on the type of camel.

Step-by-step explanation:

3 0

2 years ago

Please help me with this math problem, urgent please

cestrela7 [59]

Answer:

y = -3.5x + 15

Step-by-step explanation:

Your slope-intercept equation is always y = mx + b

Using this formula, we need to find slope first: m = (y2-y1) / (x2-x1)

Step 1: Find slope

m = (1-8) / (4-2)

m = -7/2

Step 2: Plug in into slope-intercept form

y = -3.5x + b

Step 3: Find <em>b </em>(Plug in a coordinate given)

1 = -3.5(4) + b

1 = -14 + b

b = 15

Step 4: Combine it all together

y = -3.5x + 15

And you have your final answer.

3 0

3 years ago

What is the percent of decrease on an item that went from $25 to $20?

trasher [3.6K]

$5..................

4 0

2 years ago