Question

A spinner with 12 equal sections labeled 1 -12 in spun . Find p (even number)mb

Answer 1

Answer:

The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2

Step-by-step explanation:

Given that the spinner has 12 equal sections labelled 1-12

Let S be the sample space

Then

S = {1,2,3,4,5,6,7,8,9,10,11,12}

$n(S) = 12$

Let A be the event that the outcome is an even number

Then

A = {2,4,6,8,10,12}

$n(A) = 6$

The probability of A will be given as:

$p(A) = \frac{n(A)}{n(S)}\\\\= \frac{6}{12}\\\\= \frac{1}{2}$

Hence,

The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2