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3 years ago

Slope = 7/3, y-intercept =3

Mathematics

2 answers:

Delicious77 [7]3 years ago

8 0

If it’s a graph, You start on the vertical line at 3 and go up 7 blocks and then go right 3 blocks

tekilochka [14]3 years ago

5 0

Answer:

i dont know that sorry can u halp me with english?

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(x+5)(x+1)+(x+5)(x+8)

gtnhenbr [62]

Answer:

2x² + 19x + 45

Step-by-step explanation:

(x + 5)(x + 1) + (x + 5)(x + 8) ← expand both sets of factors using FOIL

= x² + 6x + 5 + x² + 13x + 40 ← collect like terms

= 2x² + 19x + 45

5 0

2 years ago

a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seco

fomenos

Answer:

The height of the missile in the air after 11 seconds is 330 feet.

Step-by-step explanation:

The standard form for the quadratic function f(x)= $ax^2 + bx + c$ , which is the function of the parabola model.

We are given two points.

(1, 130) and (2, 240)

Here the first coordinate represents the x (time) and the second coordinate represents h(x), which is height.

Now plug these two coordinates and find the two equations.

(1, 130), the equation is

130 = a.(1)^2 + b(1) + c, where "c" is the initial height. Which is equal to zero.

Therefore, we get

130 = a + b + 0

a + b = 130 -------(1)

Now let's form the second equation using the coordinate (2, 240)

240 = $a(2)^2 + b(2) + 0$

240 = 4a + 2b -------------(2)

Now let's solve the equations (1) and (2) and find the value of "a" and "b"

a + b = 130 can be written as a = 130 - b

Here we can use the substitution method.

Now plug in a = 130 - b in the second equation, we get

240 = 4(130 - b) + 2b

240 = 520 - 4b + 2b

240 = 520 - 2b

2b = 520 - 240

2b = 280

Dividing both sides by 2, we get

b = 140

Now plug in b = 140 in a = 130 -b and find the value of a

a = 130 - 140

a = -10

Now we got a = -10 and b = 140.

We plug in a = -10 and b = 140 in the general form, we gety

h(x) = $-10x^2 + 140x + c$

Where c is the initial height, which is equal to 0.

h(x) = $-10x^2 + 140x$

Now plug in x = 11 seconds and find the height.

h(11) = -10(11)^2 + 140 (11)

= -10 (121) + 1540

= - 1210 + 1540

h(11) = 330 feet,

Therefore, the height of the missile in the air after 11 seconds is 330 feet.

6 0

3 years ago

1. Peyton has a credit card with an annual rate of 24.7% compounded monthly. She used the credit card to purchase cleaning suppl

enyata [817]

Answer:

Total interest = $3.41

Step-by-step explanation:

Since she can pay $72 each month we can divide the payments on monthly basis till all the money is paid.

The annual interest rate is 24.7%, so the monthly rate will be 24.7 ÷ 12= 2.058%

For the first month

With payment of $72 the remaining amount will be 189.56 - 72 = $117.56

Interest paid will be 0.02058 * 117.56 = $2.42

Total amount owed now will be 117.56 + 2.42 = $119.98

For the second month another payment of $72 is made

The remaining will be 119.98 - 72 = $47.98

Interest charged will be 0.02058 * 47.98 = $0.99

The amount owed will be 47.98 + 0.99 = $48.97

In the third month she will pay the remaining $47.98 which is within her monthly limit

Total interest paid = Sum of Amount paid each month - Initial amount spent

Total interest = {(72 * 2) +48.97} - 189.56 = $3.41

4 0

3 years ago

Hwllppooppppoopppppppp

babunello [35]

Answer:

Step-by-step explanation:

because they are in large sizes but small amount of time

5 0

2 years ago

Read 2 more answers

How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)

SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0

3 years ago