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3 years ago

15

Which of the following is a factor of x2 − 21x + 110?

2 answers:

ludmilkaskok [199]3 years ago

8 0

X² - 21x + 110
first you break it up into two parenthesis & since x is squared you need two x's
since 110 is positive and 21 is negitive, both of your signs need to be negitive
(x - ?)(x - ?)
then you need to think! what are the factors of 110?
Which of these factors add up to 21? those factors go in the parenthesis

Does this Help? Let me know if you need anything!

shtirl [24]3 years ago

4 0

Answer:

Option B is correct. (x-10)

Step-by-step explanation:

The given term is = $x^{2} -21x+110$

Now, to know the factors of this term, we will split 110 in a way that the factors sum upto 21.

So, 110 can be split as $11\times10$ and the sum of 11 and 10 is 21.

Now, we will split the whole term as ;

$x^{2} -10x-11x+110=0$

$x(x-10)-11(x-10)=0$

$(x-11)(x-10)$

So, the factors of $x^{2} -21x+110$ are : (x-11) and (x-10)

Therefore, out of the given options, option B is correct.

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Make x the subject of m=n + x/p

marshall27 [118]

Answer:

$\boxed{x = p(m - n)}$

Step-by-step explanation:

$= > m = n + \frac{x}{p} \\ \\ = > m = (n \times \frac{p}{p} ) + \frac{x}{p} \\ \\ = > m = \frac{pn}{p} + \frac{x}{p} \\ \\ = > m = \frac{pn + x}{p} \\ \\ = > mp = pn + x \\ \\ = > x + pn = pm \\ \\ = > x = pm - pn \\ \\ = > x = p(m - n)$

4 0

3 years ago

15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c

solniwko [45]

Answer with explanation:

Given the function f from R to $(0,\infty)$

f: $R\rightarrow(0,\infty)$

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To prove that the function is objective from R to $(0,\infty)$

Proof:

$f:(0,\infty )\rightarrow(0,\infty)$

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let $f(x_1)=f(x_2)$

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Cancel power on both side then we get

$x_1=x_2$

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get $y=x^2$

$x=\sqrt y$

The value of y is taken from $(0,\infty)$

Therefore, we can find pre image for every value of y.

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3 0

3 years ago

What the answer to this <br><br><br> -3+u=-20

yawa3891 [41]

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hope this helps!.

5 0

3 years ago

Read 2 more answers

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vichka [17]

Answer:

infinite solutions

Step-by-step explanation:

x+6+8=2x-x+14

x+6+8=x+14

x+14=x+14

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or

x=x

plug in any number

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another example

8+6+8=2(8)-8=14

22=22

5 0

3 years ago

Pls help extra points and mark brainlist

MissTica

Answer:

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Step-by-step explanation:

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6 0

3 years ago