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kodGreya [7K]
2 years ago
5

34 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 25.9 pounds and a

standard deviation of 3.8 pounds. What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?
24.6 < μ < 27.2

24.8 < μ < 27.0

24.2 < μ < 27.6

24.4 < μ < 27.4
Mathematics
1 answer:
Vlad1618 [11]2 years ago
4 0

Answer:

24.6 < μ < 27.2

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{3.8}{\sqrt{34}} = 1.3

The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.

The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.

So the correct answer is:

24.6 < μ < 27.2

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Nuetrik [128]

Answer:

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g

<em>subtract 7</em>

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<em>multiply by 3</em>

3(g-7)

<u>Therefore the expression is </u>

3g-21

8 0
2 years ago
Simplify the expression 6[8+8](3+7)] ?
krok68 [10]

Answer:

960

Step-by-step explanation:

6[8+8](3+7)

Parentheses first

6[16] (10)

Then multiply from left to right

96*10

960

7 0
3 years ago
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Suppose a baseball team has 14 players on the roster who are not members of the pitching staff. Of those 14 players, assume that
Nadusha1986 [10]

Answer: Our required probability would be 0.70.

Step-by-step explanation:

Since we have given that

Number of players = 14

Number of players have recently taken a performance enhancing drug = 3

Number of players have not recently taken a performance enhancing drug = 14-3=11

Number of members chosen randomly = 5

We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.

P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)

So, P(X≥1)=1-P(X=0)

P(X\geq 1)=1-^5C_0(\dfrac{11}{14})^5\\\\P(X\geq 1)=1-(0.786)^5\\\\P(X\geq 1)=0.70

Hence, our required probability would be 0.70.

7 0
3 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 at
Amiraneli [1.4K]

Answer:

The cubic function is f(x) = (27/32)·x  - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

3·a·(-3)² + 2·b·(-3) + c = 0

3·a·9 - 6·b + c = 0

27·a - 6·b + c = 0

3·a·(1)² + 2·b·(1) + c = 0

3·a + 2·b + c = 0

a·(-3)³ + b·(-3)² + c·(-3) + d = -3

-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

3·a + 2·b + c = 0

28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

4 0
2 years ago
I dont know the answer
Oduvanchick [21]
4/13 because the absolute value would be itself since it is positive. If it was negative then the absolute value would be positive.
8 0
3 years ago
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