All categories

4 years ago

What different between 'flow analysis using control volume method' and 'flow analysis using differential method'?

Engineering

1 answer:

tatuchka [14]4 years ago

4 0

Answer:

control volume

control volume is used to determine the flow characteristics of complex shape like turbine and compressors

differential approach

it is carried out by considering infintely small region for fluid analysis.

Explanation:

control volume:

control volume is used to determine the flow characteristics of complex shape like turbine and compressors
it is used to determine the flow velocity within in the boundaries of control volume.
it can also used for force analysis for flow.
one main disadvantage of control volume is that it doesn't provide detail information about stress and pressure variation.

differential approach:

it is carried out by considering infintely small region for fluid analysis.
solution of the fluid analysis is in the form of differential equation
it provide detail information about the flow.

You might be interested in

Is an ideal way for a high school student to see what an engineer does on a typical day but does not provide a hands-on experien

lys-0071 [83]

Answer:

Look at some engineering colleges and set up or join a public zoom meeting. For example, some colleges have sign ups for zoom calls on set dates and you‘re able to ask questions.

Explanation:

8 0

3 years ago

Read 2 more answers

A 10-m long steel linkage is to be designed so that it can transmit 2 kN of force without stretching more than 5 mm nor having a

Fed [463]

Answer:

minimum required diameter of the steel linkage is 3.57 mm

Explanation:

original length of linkage l = 10 m

force to be transmitted f = 2 kN = 2000 N

extension e = 5 mm= 0.005 m

maximum stress σ = 200 N/mm^2 = $2*10^{8} N/m^{2}$

maximum stress allowed on material σ = force/area

imputing values,

200 = 2000/area

area = 2000/( $2*10^{8}$ ) = $10^{-5}$ m^2

recall that area = $\pi d^{2} /4$

$10^{-5}$ = $\frac{3.142*d^{2} }{4}$ = $0.7855d^{2}$

$d^{2} = \frac{10^{-5} }{0.7855}$ = $1.273*10^{-5}$

$d = \sqrt{1.273*10^{-5} }$ = $3.57*10^{-3}$ m = 3.57 mm

maximum diameter of the steel linkage d = 3.57 mm

4 0

3 years ago

Create a document that includes a constructor function named Company in the document head area. Include four properties in the C

Stella [2.4K]

I have added the answer as a pic due to difficulties pasting the text here.

3 0

4 years ago

The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera

anyanavicka [17]

Answer:

note:

solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment

Download docx

7 0

3 years ago

1. Technician A says an automotive computer can scan its input and output circuits to detect incorrect voltage problems. Technic

Marta_Voda [28]

B is the correct answer

4 0

3 years ago