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VARVARA [1.3K]
3 years ago
9

Math question down below

Mathematics
1 answer:
vredina [299]3 years ago
4 0
I believe not skewed.
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The lengths of pregnancies are normally distributed with a mean of 264 days and a standard deviation of 15 days. if 36 women are
Nitella [24]
Given that a sample of 36 women is selected, the probability that the mean is between 264 days and 266 days will be found as follows:
the std deviation of the sample will be:
σ/√n
plugging the values we obtain:
15/√36
=15/6
=2.5
hence the z-score when x=264 will be:
z=(264-264)/2.5
z=0
thus:
P(x<264)=P(z<0)=0.5

the z-score when x=266 will be:
z=(266-264)/2.5
z=0.8
hence
P(x<266)=P(z<0.8)=0.7881
thus
P(264<x<266)=P(0.5<z<0.7881)
=0.7881-0.5
=0.2881

Answer: 0.2881
5 0
3 years ago
256 is what percent of 400
garri49 [273]

Answer:

64

Step-by-step explanation:

..

5 0
3 years ago
Read 2 more answers
Find the area of the shape below, giving your answer to 1 decimal place
STALIN [3.7K]

Answer:

Total area is 198.6cm²

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes.

Step one

From the given figure the two semi circles left and right can be resolved as a whole (a complete circle) with diameter d 10cm

Radius r = 10/2= 5cm

Area of circle A= πr²

A= 3.142*5²

A= 3.142*25

A= 78.55

A= 78.6cm²

Step two

The remaining part of the shape is a rectangle with length (22-10)= 12cm

I.e the 10 is as a result of the radius of the two semi circles = r+r= 5+5=10

The rectangle has a width of 10cm

Area of rectangle A=12*10= 120cm²

Hence the total surface area of the shape

Total area = 120+78.6

Total area = 198.6cm²

5 0
3 years ago
Is the line a good fit for the data?
cricket20 [7]

Answer: I think the answer is A  I might be wrong but I'm 90% sure this is right mark me BRAILIEST PLS

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Math functions. Find the common difference from this sequence. Starts with t(1). 0,4,16,36,64
yuradex [85]
The difference is that each number that comes after gets multiplied by 4

Hope I helped
6 0
3 years ago
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