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STatiana [176]
3 years ago
15

I need help figuring this out asap please

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

38.13 ft squared

Step-by-step explanation:

Since it is half of a circle we first find the area of a normal circle then divide by two.

So to find the area of  a circle it is pi times radius squared which in this case it would be 3.14 times 9 = 28.26

Then since it is a half circle we divide by two so

28.26/2 = 14.13

Then to find the area of the triangle we do 4 times 6 which is 24.

now we add the two which is 14.13 + 24 which is

38.13

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Mazyrski [523]

Answer:

3.5972174e+13 could i get brainliest please?

Step-by-step explanation:

3 0
3 years ago
Help please I'm really confused I will mark a brainliest for correct answer
max2010maxim [7]
Easy do 12 times 16 divided by two = 96

answer=96
5 0
4 years ago
Read 2 more answers
Write the exponential function.
sertanlavr [38]

Answer:

f(x) = 10*(b)^x

Step-by-step explanation:

exponential function : y=a*(b)^x

where a = y intercept and b = factor ( what you multiply by )

looking at the table the y intercept is at (0,10) so a = 10

so we now have y = 10 * (b)^x

to find the factor we simply plug in one of the ordered pairs.

note that the ordered pair chosen does not effect the outcome

i chose (2,250)

we have y = 10 * (b)^x

(x,y) = (2,250)

250 = 10 * (b)^2

divide both sides by 10

25 = b^2

take the square root of both sides

5 = b

the final equation would be f(x) = 10 * (b)^x

5 0
2 years ago
Find the rectangular coordinates of the point with the polar coordinates (3, 3 divided by 2 pi ). (1 point)
kifflom [539]

Answer:

The correct choice is (0,-3)

Step-by-step explanation:

To convert from polar coordinates to rectangular coordinates, we use the parametric equations:

x=r\cos \theta and y=r\sin \theta

The point given to us in polar coordinates is (3,\frac{3}{2}\pi).

where r=3,\theta=\frac{3\pi}{2}

x=3\cos (\frac{3\pi}{2}) and y=3\sin( \frac{3\pi}{2})

x=3(0) and y=3(-1)

x=0 and y=-3

The correct choice is (0,-3)

5 0
3 years ago
Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
andreyandreev [35.5K]
Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> <span>this is the starting equation
</span>

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

<span> Square root of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>

<span> Square root of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>


<span>Then, from here on all is wrong, but she made other additional mistakes.</span>

(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>

Later she made a mistake changing the sign of -8x to +8x


Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

3 0
3 years ago
Read 2 more answers
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