Answer:
Number of Significant figures is : 4
Scientific Notation is: 6.3 x 10^-2
EXTRA HELP
First determine the formal oxidation numbers:
N changes from +2 to +5 going from NO to (NO3)- O remains -2 the whole time Cr changes from +6 to +3
Now write the half reactions, balance the oxygens with the required number of waters and then balance the hydrogens with the required number of protons:
Oxidation half reaction:
NO(aq) + 2 H2O(l) ---> (NO3)-(aq) + 4 H+(aq) + 3 e-
Reduction half reaction:
(Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l)
Now balance the number of electrons on both sides and add them together:
2 NO(aq) + 4 H2O(l) ---> 2 (NO3)-(aq) + 8 H+(aq) + 6 e- (Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l) --------------------------------------... 2 NO(aq) + (Cr2O7)2-(aq) + 6 H+(aq) ---> 2 (NO3)-(aq) + 2 Cr3+(aq) + 3 H2O(l)
Notice that the charge is the same in both sides, which is an indication that the redox equation has been balanced correctly:
-2 + 6 = -2 + 2(+3) +4 = +4
If this is scientific notation, then the answer is 22290000, or 2.229x10^7
Explanation:
Compound A:
Mass of sulphur = 0.603g
Mass of Palladium = 0.397g
0.603g of sulphur combine with 0.397g of Palladium.
Therefore, 1g of sulphur will combine with = 0.397 / 0.603 = 0.658g of Palladium
Compound B:
Mass of sulphur = 0.301g
Mass of Palladium = 0.699
0.301g of sulphur combine with 0.699g of Palladium. Therefore, 1g of sulphur will combine with
= 0.699 / 0.301 = 2.322g of Palladium
Compound C:
Mass of sulphur = 0.151g
Mass of Palladium = 0.849g
0. 151g of sulphur combine with 0.849g of Palladium,
Therefore 1g of sulphur will combine with = 0.849/ 0.151 = 5.623g of Palladium
Therefore, the masses of Palladium which combine with a mixed mass (1g) of sulphur are in ratio
0.658 : 2.322 : 5.623 i.e 1: 4 : 9 which is a simple ratio