Not sure as don't know ratios, I think it could be 45.93g but don't take my word for it, it could be wrong.
The equations you need are moles = concentration x volume
and mass = moles x formula mass
The answer is "Liquid".
Hope I could help you!
Have a great day ;)
<span>the highest ionization energy is Be, it is higher and righter than other elements in periodic table, so it harder to remove electron from its atom</span>
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
you can google it and it pops up right away
