3 years ago

Y = (15-2x)^2(x+3) Can you guys help me with this one? All I know is the I can use the zero product Property on the x-intercepts

1 answer:

5 0

$\bf y = x(2x+5)(2x-7)\impliedby \textit{setting y = 0}
\\\\\\
0=x(2x+5)(2x-7)\implies 
\begin{cases}
0=x\\
----------\\
0=2x+5\\
-5=2x\\
\cfrac{-5}{2}=x\\
----------\\
0=2x-7\\
7=2x\\
\cfrac{7}{2}=x
\end{cases}$

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Now, we can apply in this equation that relates the new and the old values:

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