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Andre45 [30]
3 years ago
8

Y = (15-2x)^2(x+3) Can you guys help me with this one? All I know is the I can use the zero product Property on the x-intercepts

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
5 0
\bf y = x(2x+5)(2x-7)\impliedby \textit{setting y = 0}
\\\\\\
0=x(2x+5)(2x-7)\implies 
\begin{cases}
0=x\\
----------\\
0=2x+5\\
-5=2x\\
\cfrac{-5}{2}=x\\
----------\\
0=2x-7\\
7=2x\\
\cfrac{7}{2}=x
\end{cases}
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For this case we have the following function:

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What we should do is evaluate the function for the different values of the independent variable.

We have then:

For x = 8:

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For x = 1.8:

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For x = x + 8:

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