Answer:
<h2>

</h2>
Step-by-step explanation:
5 1/2 , 6 3/4 , 4 2/3
Convert to decimals
5.5 , 6.75 , 4.67
Add
16.92
She worked 16.92 hours
Convert to mixed fraction
<h2>

</h2>
Hope this helps :)
Answer:
endo 2 17uni
Step-by-step explanation:
Answer:
Just use m a t h w a y for the answer
Step-by-step explanation:
Thank me later,or dont thank me at all
Answer:

And we can solve this using the following z score formula:

And if we use this formula we got:

So we can find this probability equivalently like this:

Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
Where
and
We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean
is given by:
We want this probability:

And we can solve this using the following z score formula:

And if we use this formula we got:

So we can find this probability equivalently like this:
