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3 years ago

??????? Need help fast

Mathematics

2 answers:

Marina86 [1]3 years ago

7 0

Answer:

x=5

Step-by-step explanation:

Whenever you multiply a square root by itself it cancels out the square root because squaring a number is the opposite of taking the square root. In math inverse operations undo each other.

Kobotan [32]3 years ago

3 0

Simply ,
5

Since the product of the square root of 5 ,
Gives 5

Therefore x is also equal to 5

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

What is 12/15 × 3?(fraction times whole number)

Darina [25.2K]

Answer:

2.4 or 2 2/5

Step-by-step explanation:

When you multiply 12/15 and 3 you get 2.4 or 2 2/5

5 0

4 years ago

Read 2 more answers

What is the product? (3x-6) (2x^2 -7x+1)

STALIN [3.7K]

<u>Answer-</u>

$\left(3x-6\right)\left(2x^2-7x+1\right)=6x^3-33x^2+45x-6$

<u>Solution-</u>

Given the two polynomials are $3x-6, 2x^2 -7x+1$

So their product will be,

$=\left(3x-6\right)\left(2x^2-7x+1\right)$

Distributing the Parentheses,

$=3x\cdot \:2x^2+3x\left(-7x\right)+3x\cdot \:1+\left(-6\right)\cdot \:2x^2+\left(-6\right)\left(-7x\right)+\left(-6\right)\cdot \:1$

Applying minus-plus rules,

$=3\cdot \:2x^2x-3\cdot \:7xx+3\cdot \:1\cdot \:x-6\cdot \:2x^2+6\cdot \:7x-6\cdot \:1$

Simplifying further,

$=6x^3-33x^2+45x-6$

4 0

4 years ago

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LOTS OF POINTS

nika2105 [10]

Answer:

Step-by-step explanation:

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3 years ago

Solve the simultaneous equation 28x+32y=88 and 32x+28y=92

Alex_Xolod [135]

Answer:

Solving for x. Want to solve for y instead?

1 Factor out the common term 44.

4(7x+8y)=884(7x+8y)=88

2 Divide both sides by 44.

7x+8y=\frac{88}{4}7x+8y=

3 Simplify \frac{88}{4}

to 2222.

7x+8y=227x+8y=22

5 0

4 years ago