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3 years ago

NEED HELP ASAP WILL GIVE BRAINLIEST

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Answer:

step 2

Step-by-step explanation:

labwork [276]3 years ago

6 0

Answer:Step 1

Step-by-step explanation:

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What is the image of (1,0) after a counterclockwise rotation of 60 degrees?

Anestetic [448]

Answer:

$\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)$

Step-by-step explanation:

The coordinate has the following polar form:

$\vec r = (1, 0^{\circ})$

The image of the coordinate rotated counterclockwise 60° is:

$\vec s = (1, 60^{\circ})$

Its equivalent form in rectangular coordinates is:

$\vec s = (1\cdot \cos 60^{\circ}, 1 \cdot \sin 60^{\circ})$

$\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)$

3 0

3 years ago

The area of a gym floor is 264 square yards. the floor is 11 yards wide. how long is the floor

dmitriy555 [2]

Area = length x width

264 = length x 11

/11 /11

24 = length

ANSWER: 24 yards = length

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

3 0

3 years ago

Read 2 more answers

Michele was making tuna salad for a party. The recipe for 10 servings called for 8 oz of mayonnaise. A total of 240 people were

Anna007 [38]

1. Divide 240 by 10 = 24

2. Multiply 24 • 8 = 192

Michele will need 192 oz. of mayonnaise.

7 0

3 years ago

Read 2 more answers

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

Divided 85 lbs 2 oz by 6? PLEASE HELP its 12:00 am and I can't think right now

Ostrovityanka [42]

1 pound = 16 ounces
So we have 85 lbs and 2 oz, that is if we convert them to ounces:
85(16) + 2 = 1362 oz
so we have 1362 oz total due to the conversion factor stated above, now we only need to divide:
1362/6 = 227
that is 227 oz
or if we want the result in pounds (lbs), we can by dividing again by 16
227/16 = 14.19 lbs

6 0

3 years ago