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kenny6666 [7]
3 years ago
5

3 5/12 as a improper fraction

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

The answer is 41/12

Step by Step Explanation:

3 5/12 is equal to 3 plus the fraction 5/12, which also is equal to (3 x 12/12) plus  5/12 is equal to 36/12 plus 5/12 as a result equals 36 plus 5/12. And you get the improper fraction, 41/12.

dimulka [17.4K]3 years ago
6 0

Answer:

41/12

Step-by-step explanation:

3 x 12 = 36 then you add 5 to get 41.

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Find the value g(-2), where g is defined below.<br> g(x) = 2x^2- 4x – 4
DanielleElmas [232]

Answer:

12

Step-by-step explanation:

For this question, simply plug in -2 for x:

g(-2)=2(-2)^2-4(-2)-4\\g(-2)=2(4)+8-4\\g(-2)=8+8-4\\g(-2)=12

Hope this helps!!

8 0
3 years ago
2
never [62]

Answer:

hi

Step-by-step explanation:

Perdon si no te ayudo pero solo quiero los puntos para mis preguntas

6 0
2 years ago
Assume that y varies inversely with x. If y=9 when x=7, find y when x=2.
Aleks [24]

Answer:1.56

Step-by-step explanation:

For constant of proportionality of k,

y=(1/k)*x

If y =9,

9=7/k

K=7/9=0.78

y=0.78x

y=0.78*2=1.56

When x

4 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
Which inequality represents “35 is less than 3 times 4 more than a number”
Natasha2012 [34]
I believe it would be 3×4x<35
6 0
3 years ago
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