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Alexxx [7]
2 years ago
7

going into the final exam, which will count as two tests, amelia has test scores of 77 84 70 59 and 92. what score does amelia n

eed on the final in order to have an average score of 80?
Mathematics
1 answer:
Fudgin [204]2 years ago
6 0

Answer: 85 is your answer

Step-by-step explanation:

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The graph below shows a proportional relationship between x and y
Snezhnost [94]

Answer:

You get the answer by seeing if the line on the graph passes through the origin and if it does you see how many there is for every 1 thing.

Step-by-step explanation:

3 0
3 years ago
triangle MNO is an equilateral triangle with sides measuring 16 units What is the height of the triangle?
fiasKO [112]

see the attached figure to better understand the problem

we know that

The equilateral triangle has three equal sides

so

in the equilateral triangle ABC

AB=BC=AC=16 units

the height of the triangle is the segment BD

in the right triangle BCD

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

solve for BD

BD^{2}=BC^{2}-DC^{2}

substitute the values

BD^{2}=16^{2}-8^{2}

BD^{2}=192

BD=\sqrt{192}\ units

therefore

<u>the answer is</u>

the height of the triangle is \sqrt{192}\ units


7 0
3 years ago
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Select the choice that translates the following verbal phrase correctly to algebra: the product of k and m
romanna [79]
<em>km</em>=<em>x, </em>the product being represented by <em>x.
</em><em>
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5 0
3 years ago
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A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo
SpyIntel [72]

Answer:

R_{in}=0.2\dfrac{mL}{min}

C(t)=\dfrac{A(t)}{30000}

R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

A(t)=300+2700e^{-\dfrac{t}{1500}},$  A(0)=3000

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

R_{in}=(concentration of chlorine in inflow)(input rate of the water)

=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}

(c) Concentration of chlorine in the pool at time t

Volume of the pool =30,000 Liter

Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}

(d) Rate at which the chlorine is leaving the pool

R_{out}=(concentration of chlorine in outflow)(output rate of the water)

= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}

We then solve the resulting differential equation by separation of variables.

\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}

Taking the integral of both sides

\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}

Recall that when t=0, A(t)=3000 (our initial condition)

3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}

3 0
3 years ago
The sum of 9 and the<br> quantity 2 times a<br> number t.
noname [10]

Answer:

the question says 9 added to (2×t)

2×t

added to 9

9+(2×t)

4 0
2 years ago
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