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3 years ago

WILL GIVE BRAILIEST IF SOME ONE HELLLPPPPSSSSS

Mathematics

1 answer:

exis [7]3 years ago

8 0

Answer:

1/5 to the 18 power or

2.62144 x 10 to the -13 power.

Or just simply 5 to the -18 power

Step-by-step explanation:

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Greatest common factor for 28y^7x^4u^3 and 8x^4u^5

Nataly [62]

Answer:

Step-by-step explanation:

$28y^{7} *x^{4} *u^{3} \\8x^{4} *u^{5}$

rewrite those 2 terms to better see what they have in common

$4*7 *x^{4} *u^{3} *y^{7} \\4*2*x^{4}*u^{3} *u^{2}$

because, 4*7 =28, 4*2=8, u³*u² =u^5, and multiplication is commutative

The greatest common factor is:

$4x^{4} u^{3}$

3 0

3 years ago

5(x+3)can you tell me please

-BARSIC- [3]

What you do is you distribute the 5.

So your answer would be 5x+15

5 0

3 years ago

Read 2 more answers

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

3 years ago

Please help with 32 and 33, thank you.

PtichkaEL [24]

Answer:

32. ∛((x-7)/4) = f^(-1)(x)

33. -10x - 9

Step-by-step explanation:

32. We want to switch f(x) and x, and then solve for f(x) to get the inverse.

x = 4f(x)³ + 7

subtract 7 from both sides

x -7 = 4f(x)³

divide both sides by 4

(x-7)/4 = f(x)³

cube root both sides

∛((x-7)/4) = f(x)

make f(x) f^(-1)(x) because this is now the inverse

∛((x-7)/4) = f^(-1)(x)

the second answer is correct

33. for composition, we can treat (f · g) (x) as attached picture (content filter!), so we plug g(x) into f(x). This results in

2(-5x-7) + 5

expand

-10x - 14 + 5

add

-10x - 9

the second answer is correct

4 0

3 years ago

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

5 0

3 years ago

Read 2 more answers