<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
---
lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
answer:
1.07 hours</span>
P = $70, p = 2.5% = 0.025
q = 1 + 0.025 / 12 = 1.002
Future value of a periodic deposit:
A = P · q · ( q^30 - 1 ) / ( q - 1 )
A = 70 · 1.002 · ( 1.002^30 - 1 ) / ( 1.002 - 1 )
A = $2,166
Answer:
He will have $2.166 in 30 months.
Im pretty sure the answer is .52 I got this by subtracting the toatl by the sales tax and then dividing that total by how many pencils were bought : 6.70-.42=6.24, 6.24/12=54
The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.
<h3>For how many miles was the car driven?</h3>
It follows from the task content that the total amount paid was; $122.50.
Hence, after subtraction the constant charges, for the day and for gas, the remainder is;
$122.50 - $50 - $35
= $37.50.
Ultimately, if the charge per mile is $15, then the number of miles driven is; $37.50/$15
= 2.5 miles.
Read more on cost per unit;
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