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3 years ago

56/15 as a decimal rounded to the nearest tenth

Mathematics

1 answer:

Debora [2.8K]3 years ago

6 0

Answer:

3.7

Step-by-step explanation:

$\frac{56}{15}=3.733333333...$

$ROUND$

≈ $3.7$

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Daniel is three years older than twice his brother's age. Daniel is 17. Fill in the box with the expression that represents the

masha68 [24]

Daniel's age is X
Daniel's brother age is Y

X = 3 + ( 2Y )

Y = ( X - 3 ) / 2

In case of Daniel is 17

then his brother's age is = ( 17 - 3 ) / 2 = 7 years

4 0

3 years ago

A teacher wants to buy supplies for two of their students, Susie and John. This teacher wants to spend at least $5 on each stude

tino4ka555 [31]

X and y represent the two students.

Teacher wants to spend at least $5 in each of x and y. That means x or y could be either equal to 5 or higher than 5.
x ≥ 5
y ≥ 5

Teacher only spends under $30. That means the sum of x and y couldn't be equal to higher than 30. It should be lower than 30.
x + y < 30

The correct answer is option D

6 0

3 years ago

How is this equation completed? I cannot find any examples in the book.

djverab [1.8K]

Answer: Option D

$t_{max} =19\ s$

Step-by-step explanation:

Note that the projectile height as a function of time is given by the quadratic equation

$h = -12t ^ 2 + 456t$

To find the maximum height of the projectile we must find the maximum value of the quadratic function.

By definition the maximum value of a quadratic equation of the form

$at ^ 2 + bt + c$ is located on the vertex of the parabola:

$t_{max}= -\frac{b}{2a}$

Where $a$

In this case the equation is: $h = -12t ^ 2 + 456t$

Then

$a=-12\\b=456\\c=0$

So:

$t_{max} = -\frac{456}{2*(-12)}$

$t_{max} =19\ s$

7 0

3 years ago

Find the distance between the ordered pairs. (6, 4) and (-3, 4)

seropon [69]

Answer: = 9

There is really no steps for this answer...

4 0

2 years ago

Read 2 more answers

Find the distance between points M (6,16) and Z (-1,14) to the nearest tenth, please help step by step

insens350 [35]

The distance between 2 points P(a, b) and Q(c,d) is given by the formula:

$\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}$ ,

Apply the formula for the points M(6, 16) and Z(-1, 14):

$\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28$

which rounded to the nearest tenth is 7.3 (units)

Answer: 7.3 units

3 0

3 years ago