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olga2289 [7]
3 years ago
6

The value 0.1 meter is equivalent to 1 ____.

Mathematics
2 answers:
fredd [130]3 years ago
7 0
Centimeter I believe
r-ruslan [8.4K]3 years ago
4 0

Answer:

centimeters I think so

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iris [78.8K]
Okay so this is confusing its asking how much he ate of the left over pizza so 3/4 is 75% and he ate a quarter which is 25%  meaning he ate 25% of the left over pizza?
6 0
4 years ago
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The vertices of a pentagon are located at (-5, 3).(-5, – 3),(4, -3).(0, 0), and (4, 3).
Anton [14]
24 units because you add it all up
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3 years ago
Geometry is driving me crazy please help
Assoli18 [71]
The figure shows two intersecting chord, thus this simply can be solved using the Intersecting Chord Theorem, which states that "<span>When two chords intersect each other inside a circle, the products of their segments are equal." 
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4 years ago
The water level of a certain reservoir is depleted at a constant rate of 1000 units daily. The reservoir is refilled by randomly
Aloiza [94]

Answer:

The probability that the reservoir will be empty in the next ten days is 0.476

Step-by-step explanation:

In 10 days, the reservoir will have 10000 units of water depleted. Since the reservoir starts with almost 5000, then by gaining 8000 units it wont get emptied. It also wont get emptied if it gains 5000 or more units twice, thus, if it rains during 2 days it shoudnt get emptied.

However, note that the reservoir could get emptied if it doesnt rain in the first five days, because it will lose 5000 units, exceding its starting amount. Thus, there are only 2 possibilities for the reservoir to be emptied:

  • If it doesnt rain in the first five days
  • If it rains only once in the fisrt five days providing only 5000 units of water, and during the second period of five days it doesnt rain.

We know that the rainfall distribution is Poisson with rate 0.2 per day. In five days the rate is 0.2*5 = 1; lets call X this random variable. The probability to not have any rainfalls in 5 days is

P_X(0) = \frac{e^{-1} 1^0}{0!} = e^{-1} = 1/e

Also, the probability for it to rain just once in five days is the probability of X being equal to one

P_X(1) = \frac{e^{-1} 1^1}{1!} = 1/e

Therefore, the probability of the event 'it doesnt rain in the first five days' is 1/e, and the probability of the other event 'it rains once in the first five days, also that rain adds 5000 units of water and it doesnt rain in the other five days' is

1/e*0.8*1/e  (we multiply 1/e foe the probability that the rain gives 5000 units of water and then by the probability that it doesnt rain in the last five days).

Summing both disjoint events, we obtain that the probability that the reservoir is emptied is

1/e+ 1/e*0.8*1/e = 0.476

5 0
3 years ago
A local charity sponsors a 5K race to raise money. It receives $25 per race entry and $5,000 in donations, but it must spend $5
Katena32 [7]
<span>The charity needs at least 1001 entries to raise more than $25000. Let n be the number of race entries, i be the income of the race, and c the cost of the race. The money that the 5K brings in is given by i = 25 * n + 5000 The cost is given by c = n * 5 Now if the charity needs to raise more than 25000 then the income minus the cost must be greater than 25000. 25000 < i - c subsituting for i and c 25000 < i - c = (25 * n + 5000 ) - (5 * n) simplifying results in 25000 < 25*n - 5*n + 5000 25000 < 20*n + 5000 20000 < 20*n 1000 < n The number of entries must be greater than 1000. Since entries must be an integer the charity needs at least 1001 entries.</span>
5 0
3 years ago
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