First, we find the slope of the given line.
<span>3x − 4y = 7
-4y = -3x + 7
y = (3/4)x - 7/4
The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.
Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),
We use the point-slope form of the equation of a line.
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4) <---- check option E. Is the fraction 3/4 not there?
y + 2 = (3/4)x + 3
y = (3/4)x + 1
4y = 3x + 4
3x - 4y = -4 <------ this is choice B.
</span>
They are the same slope
they are negative inversees (they multily to get -1)
2
-1/2
use the square viewer (on TI)
The relationship between the slopes of two lines that are parallel is they are the same.
The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.
What must be done to make the graphs of two perpendicular lines appear
to intersect at right angles when they are graphed using a graphing
utility?
You add two equations together to eliminate a variable. This particular problem is nice, because it's already setup to eliminate X.
3x - 4y = 9
<span>-3x + 2y = 9
</span>
When we add these two together, 3x - 3x cancels each other out, leaving us with 0x, or nothing.
We continue with -4y + 2y (leaves us with -2y) and 9+9 (18).
-2y = 18
18/-2 = -9.
Now we have y = -9, and we can go back into the problems to solve for x.
<span>3x - 4(-9) = 9
</span>
3x + 36 = 9.
3x = -27
x = -9.
Confirm with the final equation:
-3(-9) + 2(-9) = 9
27 - 18 = 9
9 = 9 --- Confirmed.
Answer:
Step-by-step explanation:
Hello sorry I need points
