The scale that will produce the smallest drawing would be b) 1mm:50m.
First, I converted all the measurements to centimeters:
a) 1cm:500cm
b) 0.01cm:5000cm
c) 5cm:1000cm
d) 10cm:2500cm
Then, you divide the scales:
a) 0.002
b) 0.000002
c) 0.005
d) 0.004
B is the smallest number, meaning it will be the smallest scale.
Well the thing is you didn't tell us which number but if it is 12 then i strongly believe that the answer is 3/9
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Hey :) it’s (2,5) it’s C !!
