The answer is D. 42
A triangle equals 180 in total so what you would do it subtract 122 from 180 because 180 is also the angle of a straight line. You would get 58 then you add 58 and 80 to get 138. Subtract 138 from 180 and you get your answer of 42
Answer:
The equation of line is: 
Step-by-step explanation:
We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?
The equation of line in slope-intercept form is: 
where m is slope and b is y-intercept.
We need to find slope and y-intercept.
Finding Slope
Slope can be found using formula: 
We have 
Putting values and finding slope

So, we get slope: 
Finding y-intercept
Using point (-6,-2) and slope
we can find y-intercept

So, we get y-intercept b= 6
Equation of required line
The equation of required line having slope
and y-intercept b = 6 is

Now transforming in fully reduced form:

So, the equation of line is: 
Answer:
below
Step-by-step explanation:
I'm pretty sure this is the answer.
Answer:
Well, you could always just put it onto a scale to find the mass. But assuming you aren't talking about a laboratory setting. sorry if its all werid i cant really put it into how it supposed to be
The general formula is:
ρ
=
m
V
where
ρ
is density in
g/mL
if mass
m
is in
g
and volume
V
is in
mL
.
So to get the mass...
m
=
ρ
V
Or to get the volume...
V
=
m
ρ
When you have the volume and not the density, and you want to find mass, you will need to find the density yourself. It's often readily available on the internet.
Just replace "[...]" with the object you want, and if it's not exactly what you need, consider it an estimate.
These days, you should be able to search for the density of any common object.
When you have the density and volume but not the mass, then just make up a mass.
You shouldn't need specific numbers to do a problem. You can always solve a problem in general and get a solution formula. If you need to, just make up some numbers that you know how to use.
X-9=-13 because the 9 doesn't do with any of the others after the variable