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2 years ago

-3(x+2)=21 What is the answer and show the work please.

1 answer:

galina1969 [7]2 years ago

7 0

Find use the distributive property and bring down the ending result (21)
-3x-6=21

Next, add 6 on both sides and you should get:
-3x = 27

The last step is, you divide -3 from 27 and you end up with 9. So, the total answer is x = 9

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Step-by-step explanation:

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2 years ago

Given that T is the centroid of △DEF and FT=12

dlinn [17]

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

$\mathbf{TQ : FT =1 : 2}$

Where FT = 12.

Substitute 12 for FT in the above ratio

$\mathbf{TQ : 12 =1 : 2}$

Express as fraction

$\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}$

Multiply both sides by 12

$\mathbf{TQ =\frac{1 }{ 2} \times 12}$

This gives

$\mathbf{TQ =\frac{1 2}{ 2}}$

Divide 12 by 2

$\mathbf{TQ =6}$

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$\mathbf{FQ = FT + TQ}$

Substitute 12 for FT, and 6 for TQ

$\mathbf{FQ = 12 + 6}$

Add 12 and 6

$\mathbf{FQ = 18}$

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

brainly.com/question/11891965

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2 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

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$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

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3 years ago