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3 years ago

Give me anime recommendations, hope you had a good day!

Mathematics

2 answers:

nadezda [96]3 years ago

8 0

Answer:

I just started watching My Hero Academia recently, and I'm already on season four! I love it, you should check it out if you haven't already!

galina1969 [7]3 years ago

7 0

Answer:

cowboy bebop

Step-by-step explanation:

You might be interested in

Write an equation for the line in slope-intercept form, where x is the number of tickets and y is the total cost.

Feliz [49]

Answer:

Y= 21x+10.25

Step-by-step explanation:

(1,31.25) (0,10.25)

Slope= 21

21X-0=y-10.25

Y= 21x+10.25

5 0

3 years ago

An airplane flies at an elevation of 500 feet above sea level. A whale swims the same distance below sea level, what number repr

Drupady [299]

Answer:

500 below because you just do the opposite

7 0

3 years ago

Please help me with this question

sergejj [24]

Answer:

49π

Step-by-step explanation:

Circle area: πr^2

Since A to C is 14, and they're both in the center, A to B and B to C will both be 7 as a radius.

Since we know the radius, we can put it in the formula, πr^2.

We only need to solve for one circle, since both circles are the same. By solving the circle, we will put in 7 for the radius, giving us π7^2, which is 49π.

5 0

3 years ago

Whats 2+4x=5......<br> .....

sergey [27]

2+4x = 5

4x = 5-2

4x = 3

$\frac{4}{4}x = \frac{3}{4}$

x = 3/4

4 0

3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago