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2 years ago

7

Two angles are complementary three times the measure of one of the angles is 10° more than the measure of the other angle. find

the difference between the measure of the larger angle in the smaller angle

2 answers:

Mumz [18]2 years ago

8 0

Answer:

The difference is 40,

Step-by-step explanation:

Complementary angles , x+y =90

so we know angle 1, we call it 3x and angle 2 we call it y= 3x+10

so 3x +10= 90-x

4x=100

x=25

angle 1= 3(25) - 10

y= 65

65-25= 40

NikAS [45]2 years ago

5 0

Answer:

40°

Step-by-step explanation:

Let x represent one of the angles, and y represent the other one. Then we have ...

x + y = 90

3x = y +10

Substituting for y in the first equation, we have ...

x + (3x -10) = 90

4x = 100

x = 25

y = 3(25) -10 = 65

The difference between the angles is ...

y -x = 65 -25 = 40 . . . . degrees

The difference between the angle measures is 40 degrees.

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All boxes with a square base, an open top, and a volume of 60 ft cubed have a surface area given by S(x)equalsx squared plus

Karo-lina-s [1.5K]

Answer:

The absolute minimum of the surface area function on the interval $(0,\infty)$ is $S(2\sqrt[3]{15})=12\cdot \:15^{\frac{2}{3}} \:ft^2$

The dimensions of the box with minimum surface area are: the base edge $x=2\sqrt[3]{15}\:ft$ and the height $h=\sqrt[3]{15} \:ft$

Step-by-step explanation:

We are given the surface area of a box $S(x)=x^2+\frac{240}{x}$ where x is the length of the sides of the base.

Our goal is to find the absolute minimum of the the surface area function on the interval $(0,\infty)$ and the dimensions of the box with minimum surface area.

1. To find the absolute minimum you must find the derivative of the surface area ( $S'(x)$ ) and find the critical points of the derivative ( $S'(x)=0$ ).

$\frac{d}{dx} S(x)=\frac{d}{dx}(x^2+\frac{240}{x})\\\\\frac{d}{dx} S(x)=\frac{d}{dx}\left(x^2\right)+\frac{d}{dx}\left(\frac{240}{x}\right)\\\\S'(x)=2x-\frac{240}{x^2}$

Next,

$2x-\frac{240}{x^2}=0\\2xx^2-\frac{240}{x^2}x^2=0\cdot \:x^2\\2x^3-240=0\\x^3=120$

There is a undefined solution $x=0$ and a real solution $x=2\sqrt[3]{15}$ . These point divide the number line into two intervals $(0,2\sqrt[3]{15})$ and $(2\sqrt[3]{15}, \infty)$

Evaluate S'(x) at each interval to see if it's positive or negative on that interval.

$\begin{array}{cccc}Interval&x-value&S'(x)&Verdict\\(0,2\sqrt[3]{15}) &2&-56&decreasing\\(2\sqrt[3]{15}, \infty)&6&\frac{16}{3}&increasing \end{array}$

An extremum point would be a point where f(x) is defined and f'(x) changes signs.

We can see from the table that f(x) decreases before $x=2\sqrt[3]{15}$ , increases after it, and is defined at $x=2\sqrt[3]{15}$ . So f(x) has a relative minimum point at $x=2\sqrt[3]{15}$ .

To confirm that this is the point of an absolute minimum we need to find the second derivative of the surface area and show that is positive for $x=2\sqrt[3]{15}$ .

$\frac{d}{dx} S'(x)=\frac{d}{dx}(2x-\frac{240}{x^2})\\\\S''(x) =\frac{d}{dx}\left(2x\right)-\frac{d}{dx}\left(\frac{240}{x^2}\right)\\\\S''(x) =2+\frac{480}{x^3}$

and for $x=2\sqrt[3]{15}$ we get:

$2+\frac{480}{\left(2\sqrt[3]{15}\right)^3}\\\\\frac{480}{\left(2\sqrt[3]{15}\right)^3}=2^2\\\\2+4=6>0$

Therefore S(x) has a minimum at $x=2\sqrt[3]{15}$ which is:

$S(2\sqrt[3]{15})=(2\sqrt[3]{15})^2+\frac{240}{2\sqrt[3]{15}} \\\\2^2\cdot \:15^{\frac{2}{3}}+2^3\cdot \:15^{\frac{2}{3}}\\\\4\cdot \:15^{\frac{2}{3}}+8\cdot \:15^{\frac{2}{3}}\\\\S(2\sqrt[3]{15})=12\cdot \:15^{\frac{2}{3}} \:ft^2$

2. To find the third dimension of the box with minimum surface area:

We know that the volume is 60 $ft^3$ and the volume of a box with a square base is $V=x^2h$ , we solve for h

$h=\frac{V}{x^2}$

Substituting V = 60 $ft^3$ and $x=2\sqrt[3]{15}$

$h=\frac{60}{(2\sqrt[3]{15})^2}\\\\h=\frac{60}{2^2\cdot \:15^{\frac{2}{3}}}\\\\h=\sqrt[3]{15} \:ft$

The dimension are the base edge $x=2\sqrt[3]{15}\:ft$ and the height $h=\sqrt[3]{15} \:ft$

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2 years ago

Dennis and Ivy share some sweets between them in the ratio 7:4 Dennis got 42 sweets. How many does ivy get

MrRa [10]

Answer:

$Ivy = 24$

Step-by-step explanation:

Given

$Dennis : Ivy = 7 : 4$

Required

Determine the amount of sweet Ivy gets when Dennis = 42

We have:

$Dennis : Ivy = 7 : 4$ and

$Dennis = 42$

Substitute 42 for Dennis in $Dennis : Ivy = 7 : 4$

$42 : Ivy = 7 : 4$

Convert to fraction

$\frac{42}{Ivy} = \frac{7}{4}$

Cross Multiply:

$Ivy * 7 = 42 * 4$

Divide through by 7

$\frac{Ivy * 7}{7} = \frac{42 * 4}{7}$

$Ivy = \frac{42 * 4}{7}$

$Ivy = 6* 4$

$Ivy = 24$

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2 years ago

Given the system of equations, what is the value of the system determinant? x + y = 8 x - y = 10 0 -1 -2

kkurt [141]

Each X and Y in the equations don't have a number in front of them so they are all considered 1.

D = 1*(-1) - 1*(-1) = -1 -1 = -2

The answer is -2

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3 years ago

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It takes 58 pounds of seed to completely plant a 9-acre field. How many acres can be planted per pound of seed?

ozzi

Answer:

6 4/9

Step-by-step explanation:

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