I only know of 4 ways, and this might not even be correct, but here they are.
The first is verbally (a description of words) second is numerically ( by a table of values) third is visually (Graph) last is algebraically ( by a formula)
Answer:
we need the numbers... or like the coins, or something to solve it with. you need to include what was actually in here pocket lol
(4 – 2i)(6 + 2i)
FOIL
First : 4*6 =24
Outer: 4*2i = 8i
Inner: -2i* 6 = -12i
Last: -2i*2i = -4i^2 =-4(-1) =4
Add together
24+8i-12i+4
28-4i
Answer: 28-4i
<u>Answer:</u>
The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10
<u>Solution:</u>
Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2
Lets first solve 3(x – 4) ≥ 5x + 2
3(x – 4) ≥ 5x + 2
=> 3x – 12 ≥ 5x + 2
=> 3x – 5x ≥ 12 + 2
=> -2x ≥ 14
=> -x ≥ 7
=> x ≤ -7
All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7
Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.
Answer:
Below in bold.
Step-by-step explanation:
Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.
Here a1 = 5 and d = 8-5 = 3.
So an = 5 + 3(n - 1)
15th term a15
= 5 + 3(15 - 1)
= 5 + 42
= 47.
