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Naily [24]
3 years ago
15

You have sold your home and would like to travel the European country side. While you are out of the country, you would like the

profit that you made on the sale of your home to gain interest while you are away in Europe. You made a profit of $25,000 on the sale of your home, and you invest this amount into an account paying 7.8% interest compounded annually. If you are to withdraw from the account over a 5 year period, such that by the end of the five year period there is zero dollars in the account, how much annually will you be able to withdraw from the account?
a.
$5,821.22
c.
$6,012.10
b.
$5,959.02
d.
$6,228.44
Mathematics
2 answers:
Ivahew [28]3 years ago
8 0
25000=X [((1-(1+0.078)^(-5))/0.078]
Solve for x
X=6228.44
Sholpan [36]3 years ago
7 0

Answer:

D. $6228.44

Step-by-step explanation:

We are given that,

Present value of the profit = $25,000

Rate of interest = 7.8% = 0.078

Time Period = 5

Now, we have the annuity formula P=\frac{r \times PV}{1-(1+r)^{-n} }, where P = annual withdrawn amount, PV = present value, r = rate of interest and n= time period.

So, substituting the given values gives,

P=\frac{0.078 \times 25000}{1-(1+0.078)^{-5} }

i.e. P=\frac{1950}{1-(1.078)^{-5} }

i.e. P=\frac{1950}{1-0.6869}

i.e. P=\frac{1950}{0.3131}

i.e. P=0.6228.042

So, we get that the annual amount closest to the obtained P we can withdraw is $6,228.44.

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________________________________________________________

Explanation:

________________________________________________________
Given the original function:  

" c(y) = (5/9) (x <span>− 32) " ; in which "x = f" ; and "y = c(f) " ;
________________________________________________________
</span>→  <span>Write the original function as:  " y = </span>(5/9) (x − 32) " ; 

Now, change the "y" to an "x" ; and the "x" to a "y"; and rewrite; as follows:
________________________________________________________
    x = (5/9) (y − 32) ; 

Now, rewrite THIS equation; by solving for "y" ; in terms of "x" ; 
_____________________________________________________
→ That is, solve this equation for "y" ; with "c" as an "isolated variable" on the
 "left-hand side" of the equation:

We have:

→  x  =  " (  \frac{5}{9}  ) * (y − 32) " ;

Let us simplify the "right-hand side" of the equation:
_____________________________________________________

Note the "distributive property" of multiplication:
__________________________________________
a(b + c) = ab + ac ;  <u><em>AND</em></u>:

a(b – c) = ab – ac
.
__________________________________________

As such:
__________________________________________

" (\frac{5}{9}) * (y − 32) " ; 

=  [ (\frac{5}{9}) * y ]   −  [ (\frac{5}{9}) * (32) ] ; 


=  [ (\frac{5}{9}) y ]  − [ (\frac{5}{9}) * (\frac{32}{1})" ;

=  [ (\frac{5}{9}) y ]  − [ (\frac{(5*32)}{(9*1)} ] ; 

=  [ (\frac{5}{9}) y ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ (\frac{5y}{9}) ]  −  [ (\frac{(160)}{(9)} ] ; 

= [ \frac{(5y-160)}{9} ] ;  
_______________________________________________
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→  " x  =  \frac{(5y-160)}{9} "  ;

We want to rewrite this; solving for "y";  with "y" isolated as a "single variable" on the "left-hand side" of the equation ;

We have:

→  " x  =  \frac{(5y-160)}{9} "  ; 

↔  " \frac{(5y-160)}{9} = x ; 

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Now, add "160" to each side of the equation; as follows:
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→  5y − 160 + 160 = 9x + 160 ; 

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 →  Now, remember we had substituted:  "y" for "c(f)" ; 

Now that we have the "equation for the inverse" ;
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→  Answer choice:  [C]:  " f(c) = \frac{9}{5} c  + 32 " .
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