let the 2 integers be x and x + 2.
so we have the equation:-
3(x + 2) = x - 10
3x + 6 = x - 10
2x = -16
x = -8
the integers are -8 and -6 answer
[x-1]=5x+10
We have two equations:
1) x-1=5x+10
x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4
2) x-1=-(5x+10)
x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2
we have two possible solutions:
solution₁; x=-11/4
solution₂: x=-3/2
we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4 - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4 + 10
[-15/4]=(-55+40) /4
15/4≠-15/4 This solution don´t work.
2) x=-3/2
[x-1]=5x+10
[-3/2 - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2 + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.
Therefore:
Answer: x=-3/2.
Is it a yardstick? It has 2 ft of the edges and one ft in the middle.
Hey there!!
Given equation :
... 2 ( x - ( 3 + 2x ) + 9 ) = 3x - 8
Using the distributive property.
... 2 ( x - 3 - 2x + 9 ) = 3x - 8
... 2 ( -x + 6 ) = 3x - 8
Using the distributive property.
... -2x + 12 = 3x - 8
Subtracting 12 on both sides.
... -2x = 3x - 8 - 12
... -2x = 3x - 20
Subtracting 3x on both sides.
... -2x - 3x = -20
... -5x = -20
Dividing by -5 on both sides.
... x = -20 / -5
... x = 4
<em>Hence, the answer is 4. </em>
Hope my answer helps!