All categories

3 years ago

Which equation in point-slope form contains the points (6, 2) and (2, 4)?

Mathematics

1 answer:

ziro4ka [17]3 years ago

5 0

Y-2 = m (x-6), where m = (2-4)/(6-2) = -2/4 = -1/2
y-2 = 1/2 (x-6)

You might be interested in

Marc wants to guess how many marbles are in a box that has a height of 18 inches. He calculates that there are 32 marbles in a h

Rainbow [258]

So every 5 inches in height, there are 32 marbles. You want to know how many marbles there are per 18 inches in height.

$\frac{32}{5} = \frac{x}{18}$

To get from 5 to 18, you multiply by 3.6.

Do the same thing to the numerator; 32 × 3.6 = 115.2.

Since 0.2 marbles is no marbles, you round down.

There are 115 marbles in the box.

♡ Hope this helps! ♡

❀ 0ranges ❀

8 0

2 years ago

A rectangular garden has a walkway around it. The area of the garden is 4(6.5x+3.5). The combined area of the garden and the w

alexdok [17]

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

3 0

2 years ago

Where do you place the parentheses in the expression 4+3^2•5-2 to equal 31

Pani-rosa [81]

4+3^2•5-2

$4+3^2\cdot(5-2)=4+9\cdot3=4+27=31$

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

8 0

2 years ago

142/80 into mixed number

Cerrena [4.2K]

80 goes into 142 once, so one is our whole number. there are still 62 / 80 left, so we reduce this fraction. The answer is 1 $\frac{31}{40}$

8 0

2 years ago

For the month of January in a certain city, 42% of the days are cloudy. Also in the month of January in the same city, 41% o

zalisa [80]

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = $P(A)=0.42$

The probability that the days are cloudy and rainy = $P(A\cap B)=0.41$

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

$P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762$

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy = 0.9762

7 0

3 years ago