How to divide fractions with concrete models? PLEEASE I HAVE A TEST TOMORRW, I WILL GIVE FIRST ANSWER THAT IS SMART BRANLIEST

Mathematics

1 answer:

Leya [2.2K]2 years ago

8 0

Answer:

So first, there is an acronym for the strategy, KFC.

°π°

Keep the first fraction. Ex, 4/5 ÷ 1/5

Flip the second fraction. Ex, 4/5 ÷ 5/1

Change symbol. Ex, 4/5 ÷ 5/1 turns into 4/5<em>x</em>5/1

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In ΔLMN, MN = 15, NL = 20, and LM = 6. Which list has the angles of ΔLMN in order from smallest to largest?

Gnom [1K]

Answer:

m<N, m<L, m<M

Step-by-step explanation:

The angle that sees the longest side length has the bigger angle measurement

so the angles would be listed as following :

from smallest to largest :

m<N, m<L, m<M

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2 years ago

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Serhud [2]

Answer:

It was an exponential increase

In 3 months, the bill will be $285.61

Step-by-step explanation:

First, this scenario is exponential, because the price of food is increasing with a percentage, based on the price that it was the previous amount.

Next, to find what the bill will be in 3 months, an equation needs to be made representing the situation.

Use the standard exponential equation: y = ab^x, where a is the initial amount, b is the growth rate, and x is the amount of time.

Plug in the values we know:

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3 years ago

A jar is filled with only dimes and quarters. The jar contains a total of 60 coins and the value of the jar is $11.25. How many

inessss [21]

Answer:

35 quarters

Step-by-step explanation:

This situation has two unknowns - the total number of dimes and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.

$d+q=60$ is an equation representing the total number of coins
$0.10d+0.25q=11.25$ is an equation representing the total value in money based on the number of coin. 0.10 and 0.25 come from the value of a dime and quarter individually.

We write the first equation in terms of q by subtracting it across the equal sign to get $d=60-q$ . We now substitute this for d in the second equation.