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yanalaym [24]
4 years ago
13

Write the number -0.000000000000384 in scientific notation.

Mathematics
1 answer:
dsp734 years ago
8 0

Answer:

Step-by-step explanation:

-0.000000000000384 = -3.84 * 10⁻¹³

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The price of an item has been reduced by 65%. The original price was $25.
SVEN [57.7K]
25 • 0.65 = 16.25
25 - 16.25= 8.75
The new price is $8.75
4 0
3 years ago
What two-dimensional figure will result from slicing this rectangular pyramid parallel to the base?
andreev551 [17]

Answer: The answer is D. Trapezoid.    


Step-by-step explanation:  As shown in the attached figure, a rectangular pyramid  ABCDE is drawn. We are slicing this rectangular pyramid parallel to the base BCDE at the points F, G, H and I.

We can clearly see from the figure that upper half of the sliced figure will be similar to the pyramid BCDE and the lower sliced figure will be a trapezoid. These are the three-dimensional figures.

Also, the sliced two-dimensional figure FGHI will be a rectangle, because

the pyramid is a rectangular one and so,  FI=GH, FG=HI and all the angles are right angles.

Thus, the resulting two-dimensional figure will be a rectagle.


7 0
3 years ago
Read 2 more answers
Solve -x^2 + 4x +10 = 0 by using the "Solving the square method"
Pavel [41]

Answer:

x =  - 2 +  \sqrt{14}  \:  \: or  \:  \: x =  - 2 -  \sqrt{14}

Step-by-step explanation:

{x}^{2}  - 4x - 10 = 0 \\  {x}^{2}  - 4x = 10 \\  {x}^{2}  - 2(2x) = 10 \\  {x }^{2}  - 2(2x) + 4 = 10 + 4 \\ {(x + 2)}^{2}  = 14 \\ x + 2 =  \sqrt{14}  \:  \:  \:  \: or \:  \:  \: x + 2 =  -  \sqrt{14}

3 0
3 years ago
Look at equations below find a pair of equations whose lines are perpendicular
LekaFEV [45]

Answer:

first one

Step-by-step explanation:

These line equations are all of the form  y = mx + b   where m is the slope

   if m = slope     perpindicular m = - 1/m

The only one that fits this description is the first one

    slope =  1/5     perpindicular = - 1/(1/5) = -5

3 0
2 years ago
Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .
adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$   (De-Morgan's law)

Let  $x \in \bar{A} \cap \bar{B}, $ then $x \in \bar{A}$ and $x \in \bar{B} $

and so $x \notin \bar{A}$ and $x \notin \bar{B} $.

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$   .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and  $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$  .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0
3 years ago
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