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3 years ago

Estimate the quotient of 57.8 divided by 81

Mathematics

1 answer:

Rudik [331]3 years ago

3 0

Right answer is 1.4013841

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Solve for x thanks!!!!!

IrinaK [193]

Answer:

x=5

Step-by-step explanation:

Since the angle with the expession and the one that has a measure of 58 and corresponding, they have equal measure. This helps us write an equation-

12x-2=58

now, solve

-2+2=0, 58+2=60

12x=60

12x/12=60/12

x=5

hope this helps:)

please crown me brainliest!!!

3 0

3 years ago

Read 2 more answers

What angle measures have tangent 1

kati45 [8]

Step-by-step explanation:

the angle should be 60°

7 0

3 years ago

I need help with this problem

alexandr402 [8]

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4

Finally, this should be re-written as

4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30 4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

2x^2y^8 1

7 0

3 years ago

Factor 10x^3 8x^2 - 6x. (<br> a.2x(5x 4x - 3) (<br> b.2x(5x 4x^2- 3) (<br> c.2x(5x^2 4x - 3)

Semmy [17]

You have to look at the equation and find a common factor bettween all parts. SO, we see they all have an x, so that is the first thing you can factor out. They also have
2x(5x2 4x -3) C

4 0

3 years ago

last year 1/5 of the students in your class played a sport this year 10 students join the class five of the new students play a

tino4ka555 [31]

Answer:

Step-by-step explanation:

last year 1/5 of the class played sports, so s = (1/5) c

the next year, s increased by 5, c increased by 10 and the fraction changed to 1/4, so for the next year (s+5) = (1/4)(c+10)

To solve this we can substitute s = (1/5)c from the first equation into the second, so

((1/5)c + 5)=(1/4)(c+10), simplify both sides

(1/5)c + 5 = (1/4)c + 10/4, simplify 10/4 to 5/2

(1/5)c + 5 = (1/4)c + 5/2, multiply both sides by 20 to eliminate fractions (least common multiple of 2, 4 and 5)

4c + 100 = 5c + 50, subtract 4c, subtract 50 from both sides

50 = c, number of students in class last year was 50, this year is 10 more, so this year is 60

5 0

3 years ago