From left to right:
(4 3/8), (6 2/9), (3/10), (5 1/15), (3 5/12), (1 7/16), (5 9/40), (2 7/22), (3/16), (3 1/9), (2 9/28), (5 1/8), (7 3/16), (5 3/20), (3 11/40), (3 3/14)
Answer:
A. The students tend to have fewer siblings than the teachers.
Step-by-step explanation:
First we need to draw the dot plots correctly. If you count both sides they have 20 each.
Now, clearly none have fewer nobody here yet has more or less but going on to the next step.
Multiply exactly the number of siblings times how many people chose that many siblings. Ex: 2 (siblings) times 7 (people who has 2 siblings) = 14. And so on.
On the Student A, we get a total of 41 people having sibling, if you count the 0's then there were a total of 43 people. But now on the Teacher's A Dot Plot, we have a total of 68 people, if you include the 0 then we have a total of 69.
So the answer is A. The students tend to have fewer siblings than the teachers.
Answer: g = 15 . Georgia has 15 electoral votes.
Step-by-step explanation:
Mental math: How many do I need to make up the difference?
counting by 5s: 5, 10 15, 20.
6 is one more than 5.
From 5, three more 5's gets us close to 20. It works.
6 + 15 = 21
The fraction of a defective item getting by both inspectors is =
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 = .
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = .
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) = × = = = 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
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