All categories

3 years ago

Lis 10 múltiples of 8

Mathematics

2 answers:

andrey2020 [161]3 years ago

6 0

10 times 8 would = 80

victus00 [196]3 years ago

5 0

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

You might be interested in

what is the equation of the line that passes through (3,-1) and is parallel to y=-4X + 1? give your answer in slope-intercept fo

Butoxors [25]

the answer is y=4x-11

use y+1=4x-12

move 1 to negative because move to the other side

so the answer is y=4x-11

5 0

3 years ago

What is the code for the linear equations digital escape room puzzle 3

likoan [24]

Linear equation:

y=mx+b

4 0

2 years ago

How do you simplify the fraction 252 over 288?

VARVARA [1.3K]

GCF = 36

We can reduce the fraction by dividing
the numerator and denominator by 36
and get our simplified answer


 252 ÷ 36 / 288 ÷ 36 =

 7 / 8

3 0

4 years ago

Read 2 more answers

According to a survey of 500, the mean income before taxes of consumer units (i.e., households) inthe U.S. was $60,533 with a st

ioda

Answer:

The margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

Step-by-step explanation:

We are given that according to a survey of 500, the mean income before taxes of consumer units (i.e., households) in the U.S. was $60,533 with a standard error of 717.51.

Margin of error tells us that how much our sample mean value deviates from the true population value.

Margin of error is calculated using the following formula;

Margin of error = $Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}$

where, $\alpha$ = level of significance = 1 - confidence level

= 1 - 0.95 = 0.05 or 5%

Standard of Error = $\frac{\sigma}{\sqrt{n} }$ = 717.51

Now, the value of z at 2.5% level of significance ( $\frac{0.05}{2} =0.025$ ) is given in the z table as 1.96, that means;

Margin of error = $Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}$

= $1.96 \times 717.51$ = 1406.32

Hence, the margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

3 0

4 years ago

Plz solve this problem of trigonometry i am an aakashian

makkiz [27]

Step-by-step explanation:

$\bf L.H.S = \tt \dfrac{sec\: \theta + tan \: \theta - 1}{tan \: \theta - sec \: \theta + 1} \\ \\$

$: \implies \tt \dfrac{\frac{1}{cos \: \theta} + \frac{sin \: \theta}{cos \: \theta} - 1}{ \frac{sin \: \theta}{cos \: \theta} - \frac{1}{cos \: \theta} + 1 } \: = \dfrac{1 + sin \: \theta - cos \: \theta}{sin \: \theta + cos \: \theta} \\ \\$

$: \implies \tt\dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta + (cos \: \theta - 1)} \: \times \: \dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta - (cos \: \theta - 1)} \\ \\$

$: \implies \tt\dfrac{ sin^{2} \: \theta + cos^{2} \: \theta + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: (cos \: \theta - 1)}{sin^{2} \: \theta - (cos \: \theta - 1)^{2} } \\ \\$

$: \implies \tt\dfrac{1 + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - sin^{2} \: \theta - cos^{2} \: \theta + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 (1 - \: cos \: \theta )- 2 \: sin \: \theta (1 - \: cos \: \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2} \: \theta} \\ \\$

$: \implies \tt\dfrac{(2 + 2 \: sin \: \theta) \: \cancel{(1 - cos\: \theta)}}{2 \: cos \: \theta \: \cancel{(1 - cos \: \theta)}} \: = \: \dfrac{1 + sin \: \theta}{cos \: \theta} \\ \\$

$: \implies\tt\dfrac{1 + sin \: \theta}{cos \: \theta} \: \times \: \dfrac{1 - sin \: \theta}{1 - sin \: \theta} \\ \\$

$: \implies\tt\dfrac{1 + sin^{2} \: \theta}{cos \: (1 - sin \: \theta)} \\ \\$

$: \implies\tt\dfrac{cos^{2} \: \theta}{cos \: \theta (1 - sin \: \theta)} \\ \\$

$: \implies\tt\dfrac{cos \: \theta}{1 - sin \: \theta} \: = \: \bf{ R.H.S}\\ \\$

$\huge\bigstar \:\underline{\red{\sf Hence, Proved}} \: \bigstar \\$

6 0

4 years ago