The formula for the lateral surface area of a right circular cone is:
where r is the radius of the base, and l is the slant height.
Plugging in the values we get:
If 3/5 of the tree is unripe, then 2/5 of the tree is ripe.
2/5 = 0.4
0.4 x 100 = 40% of the tree is ripe
Answer:
Option A
Step-by-step explanation:
That is your answer
Answer:
B
Step-by-step explanation:
B-X=A
or
B-A=X
or
X=B-A
![X=\left[\begin{array}{ccc}-5&-1&6\\4&1&2\\0&-3&2\end{array}\right] -\left[\begin{array}{ccc}-1&-2&3\\4&8&-6\\0&1&5\end{array}\right] \\=\left[\begin{array}{ccc}-5+1&-1+2&6-3\\4-4&1-8&2+6\\0-0&-3-1&2-5\end{array}\right] \\=\left[\begin{array}{ccc}-4&1&3\\0&-7&8\\0&-4&-3\end{array}\right]](https://tex.z-dn.net/?f=X%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%26-1%266%5C%5C4%261%262%5C%5C0%26-3%262%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-2%263%5C%5C4%268%26-6%5C%5C0%261%265%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%2B1%26-1%2B2%266-3%5C%5C4-4%261-8%262%2B6%5C%5C0-0%26-3-1%262-5%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%261%263%5C%5C0%26-7%268%5C%5C0%26-4%26-3%5Cend%7Barray%7D%5Cright%5D)
The answer to the problem is 15.
First, you must set up the equation.
Then, you must eliminate double negatives.
Next, divide -56 by -7.
Finally, add like terms.
