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Naddik [55]
2 years ago
9

A data set is normally distributed with a mean of 27 and a standard deviation of 3.5. Find the z-score for a value of 25, to the

nearest hundredth.
Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0

Answer:

z score = .2843

Step-by-step explanation:

25 is 2 below 27

   this is  2/3.5 = .5714  S.D. below mean

      z-score  . 2843

You might be interested in
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
Use the power series representation of f(x)=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1-5x%7D%20" id="TexFormula1" t
Sergeu [11.5K]
For |5x|, we have

\dfrac1{1-5x}=\displaystyle\sum_{n\ge0}(5x)^n

and so

g(x)=\dfrac{15}{1-5x}=15\displaystyle\sum_{n\ge0}(5x)^n=3\sum_{n\ge0}5^{n+1}x^n

which is, again, only valid for |5x|.
4 0
3 years ago
Please helppp. I’ll mark the Brainlessly pleaseee help
Pepsi [2]

Step-by-step explanation:

The answer is the 2nd one, the denominator is greater than the numerator because if you add 2 AND x its gonna ge a bigger number than just x alone

4 0
3 years ago
How do you write 55 another way
CaHeK987 [17]
It can also be written as fifty-five.
7 0
3 years ago
Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8
Lelu [443]
It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod <span>9</span><span> are </span><span><span>1</span><span>,4,7</span></span><span> which are came from </span><span><span>1,2,</span><span>4.</span></span><span> </span>Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.
5 0
2 years ago
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