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Liula [17]
3 years ago
10

Example 2

Mathematics
1 answer:
Arada [10]3 years ago
5 0

Answer:

y=x-2

Step-by-step explanation:

If you have drawn the graph of y = x^2 - 3x + 1.

To determine the equation of the line which  should be drawn to solve the equation:  x² - 4x +3=0

Simply carry out the subtraction: x^2 - 3x + 1 -(x^2 - 4x +3)

\implies x^2 -3x + 1-x^2 + 4x -3 \\= x^2 - x^2+ 4x - 3x-3  + 1\\=x-2

The equation of the line which should be drawn is: y=x-2

What this means is simply:

If

y = x^2 - 3x + 1$ and $y=x-2,$ then:\\x^2 - 3x + 1=x-2\\x^2 - 3x + 1-x+2=0\\x^2 - 4x + 3=0

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