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2 years ago

A yogurt costs 45p. How many yogurts can be bought for five pounds?

Mathematics

1 answer:

LekaFEV [45]2 years ago

3 0

1/9 of a yogurt can be bought with 5 pounds.

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Maria and her friend ride their bikes. They start at 12:47 and end at 2:29. How long did they ride their bikes for?

IRINA_888 [86]

Answer:

Their bide ride was 1 hour and 42 minutes

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3 years ago

A refrigerator costs $580 a year to run. A family purchases a new one for $1200 that will save them 22% annually in energy costs

NeTakaya

Answer:

It will take nine years and four months for the refrigerator to pay for itself.

Step-by-step explanation:

The new refrigerator which costs $1200, saves the family 22% annually in energy cost.

Since the old refrigerator costs $580 to run, we want to determine how many years it will take for 22% of $580 per year to make $1200.

22% of $580

= 580 × 0.22

= 127.6

That is, it saved then $127.6 per year.

Now,

$1200/127.6

≈ 9.4

Which means, it will take 9 years and 4 months for the refrigerator to pay for itself.

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2 years ago

The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?

Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

Step 1: You need to create a equation first:

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

How did I make the equation?

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13 ALL CONSECUTIVE ODD NUMBERS

Step 2: Simplifying the equation

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

Step 3: Solving the equation, with explanation

5n + 20 = 2555 Subtract 20 on both sides

5n = 2535 Isolate the variable by dividing 5 on both sides

n = 507

Step 4: Plug in the value

n + n + 2 + n + 4 + n + 6 + n + 8

507, 507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

Step 5: Solve the sum of the first, third, and last integer

507 + 511 + 515 = 1533

Step 6: THE ANSWER

1533

<h3>Hope this helps!!! </h3><h3>Please mark this as brainliest!!! </h3><h3>Thank You!!! </h3><h3>:)</h3>

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You need to look at website see what your witting about a good way to if the website has a phone number call and find on on your topic and ask questions about it

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