What is x +92 x 32 when x is 50

A dog jumps straight up in the air to catch a ball and lands on the ground 1.3 s later. Let h(t) represent the dog’s height, in

slamgirl [31]

The given question have mistake. The correct question is written below.

Question:

A dog jumps straight up in the air to catch a ball and lands on the ground 6.37 s later. Let h(t) represent the dog’s height, in meters, t seconds after he leaves the ground. Which equation models the dog’s height for a given time t?

Answer:

Option B:

$h(t)=-4.9 t^{2}+6.37t$

Solution:

<u>General formula for the height of the projectile over time:</u>

(1) $h(t)=-16 t^{2}+v t+s$

Where h = height in feet, t = time, v = initial velocity and s = initial height (feet)

(2) $h(t)=-4.9 t^{2}+v t+s$

Where h = height in meters, t = time, v = initial velocity and s = initial height(meter)

Given initial velocity = 6.37 s and initial height is 0.

The height of the dog is in meters.

So, use second formula and substitute v = 6.37 and s = 0.

$h(t)=-4.9 t^{2}+v t+s$

$h(t)=-4.9 t^{2}+6.37t+0$

$h(t)=-4.9 t^{2}+6.37t$

Hence option B is the correct answer.

6 0

3 years ago

Suppose that K is a random variable. Given that Upper P (negative 3.95 less than or equals Upper K less than or equals 3.95 )equ

Irina-Kira [14]

Answer:

P [ K > 3.95] = 0.5633

Step-by-step explanation:

The interpretation of the given question goes thus;

Suppose that K is a random variable

P[-3.95 ≤ K ≤ 3.95] = 0.725

where; P [ + 3.95 < K ] = P [K < - 3.95]

P[K< 3.95] - P [K > - 3.95] =0.725

P [K < 3.95] - [ 1- P[K < 3.95]] = 0.725

P[k < 3.95] - 1 + P [ K < 3.95] = 0.725

3.95 P [ K < 3.95] -1 = 0.725

3.95 P [ K < 3.95] = 1.725

P [ K < 3.95] = 1.725/3.95

P [ K < 3.95] = 0.4367

P [ K > 3.95] = 1 - P[K< 3.95]

P [ K > 3.95] = 1 - 0.4367

P [ K > 3.95] = 0.5633

8 0

3 years ago

During the 2013 regular NBA season, DeAndre Jordan of the Los Angeles Clippers had the highest field goal completion rate in the

melomori [17]

Answer:

a) The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=80, p=0.613)$

b) $\mu = n*p = 80*0.613= 49.04$

$\sigma = \sqrt{np(1-p)}= \sqrt{80*0.613*(1-0.613)}= 4.356$

c) For this case we can use the following excel code:

"=BINOM.DIST(60,80,0.613,FALSE)"

And we got 0.00355

d) $P(X>50) 1-P(X \leq 50)$

And we can use the following excel code:

"=1-BINOM.DIST(50,80,0.613,TRUE)"

And we got 0.3718

Step-by-step explanation:

Assuming the following questions:

a) What is the probability distirbution for X?

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=80, p=0.613)$

b) Using formula calculate the mean and standard deviation of X

By properties we have:

$\mu = n*p = 80*0.613= 49.04$

$\sigma = \sqrt{np(1-p)}= \sqrt{80*0.613*(1-0.613)}= 4.356$

c) Use your calculator to find the probability that DeAndre scored with 60 of these shots

For this case we can use the following excel code:

"=BINOM.DIST(60,80,0.613,FALSE)"

And we got 0.00355

d) Find the probability that DeAndre scores with more than 50 of these shots

We want this probability:

$P(X>50) 1-P(X \leq 50)$

And we can use the following excel code:

"=1-BINOM.DIST(50,80,0.613,TRUE)"

And we got 0.3718

8 0

3 years ago

What is the volume of a<br> cube that has one side of ||<br> cm?

yulyashka [42]

Answer:

5

Step-by-step explanation:

633 yess sjs this is rhe im doing this for points

8 0

3 years ago

Read 2 more answers

Seventy-two percent of all observations fall within one standard deviation of the mean if the data is normally distributed. a. T

Deffense [45]

Answer:

I think this answer is A.

6 0

3 years ago