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Sever21 [200]
3 years ago
15

Solve for x 1 − 6x ≤ − 17 please help i am crying rn

Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer:

x \geqslant 3

Step-by-step explanation:

subtract 1 from both sides

-6x<-17-1

simplify

-6x<-18

divide by 6 on both sides

x>3

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Please answer!! It’s for biology on oddesseyware.
lbvjy [14]

Inverse of p—>q is ~p—>~q

Basically the third choice.

Inverse swaps the truth value of both statements.

Converse swaps the both of statements. (Ex. p—>q then converse would be q—>p)

3 0
3 years ago
Please I need this done quickly Explain the answer please
Mashutka [201]
When writing an equation of a line, keep in mind that you ALWAYS need two pieces of information when you go to write an equation:
1. ANY point on the line
2. Slope (m)
3. Y-intercept (b)

Once you have these two pieces of information, you plug the x and y values from your point and the slope (m) value into the slope-intercept form, y = mx + b.


Start by solving for the slope of each line. We need two ordered pairs (x, y) from each line to solve for the slope:

Offer A:
(0, 400) and (80, 700)

Let (x1, y1) = (0, 400)
(x2, y2) = (80,700)

m = (y2 - y1)/(x2 - x1)
m = (700 – 400)/(80 – 0) = 300/80 = 15/4

Therefore, the slope (m) for Offer A = 15/4

Next, we need the y-intercept. The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. One of the points we used for solving the slope for Offer A reflects the description for the y-intercept, which is point (0, 400). The y-coordinate is 400–this is the y-intercept of the line.

Now, we can establish the linear equation for Offer A: y = 15/4x + 400

Do the same steps for the other offer:

Offer B:
(0, 500)) and (100,900)
Let (x1, y1) = (0, 500)
(x2, y2) = (100,900)

m = (y2 - y1)/(x2 - x1)
m = (900 - 500)/(100 – 0) = 400/100 = 4

Therefore, the slope for Offer B is 4.

Next, we need the y-intercept. For Offer B, the line crosses at point (0, 500). The y-coordinate, 500 is the y-intercept (b) of the line.

The linear equation for Offer B is:
y = 4x + 500



**NOTE: please double-check the coordinates that I used for solving the slopes of each line before using my inputs. I had a slight difficulty going through the coordinates of your graph because it’s a bit blurry (using my phone to write this post).

Please mark my answers as the Brainliest if you find my explanations helpful :)
5 0
3 years ago
Can someone please help me with this math question?
KATRIN_1 [288]
I think it would be (D. 88)

~Hope This Helped~
3 0
3 years ago
What is the common denominator for 1/2 and 1/8
Snowcat [4.5K]

Answer:


Step-by-step explanation:

8 would be the common denominator, so you would multiply the 1/2 by 4/4 to get 4/8, and if you needed to add, 4/8 + 1/8 is 5/8

7 0
4 years ago
Read 2 more answers
Which is equivalent to V180x11 after it has been simplified completely?
inna [77]

Question:

Which is equivalent to \sqrt{180x^{11}} after it has been simplified completely?

Answer:

\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}

Step-by-step explanation:

Given

\sqrt{180x^{11}}

Required

Simplify

We start by splitting the square root

\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}

Replace 180 with 36 * 5

\sqrt{180x^{11}} = \sqrt{36 * 5} *  \sqrt{x^{11}}

Further split the square roots

\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} *  \sqrt{x^{11}}

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{11}}

Replace power of x; 11 with 10 + 1

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10 + 1}}

From laws of indices; a^{m+n} = a^m * a^n

So, we have

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10} * x^1}

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10} * x}

Further split the square roots

\sqrt{180x^{11}} = 6*\sqrt{5} *  \sqrt{x^{10}} * \sqrt{x}

From laws of indices; \sqrt{a} = a^{\frac{1}{2}}

So, we have

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{10*\frac{1}{2}} * \sqrt{x}

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{\frac{10}{2}} * \sqrt{x}

\sqrt{180x^{11}} = 6*\sqrt{5} *  x^{5} * \sqrt{x}

Rearrange Expression

\sqrt{180x^{11}} = 6 *  x^{5} * \sqrt{5} * \sqrt{x}

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}

From laws of indices; \sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}

So, we have

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}

\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}

\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}

<em>The expression can no longer be simplified</em>

Hence, \sqrt{180x^{11}} is equivalent to 6x^{5}\sqrt{5x}

7 0
3 years ago
Read 2 more answers
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