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3 years ago

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Find the solutions to x^2=27 A x= +/- 9 √3 B x= +/- 3 √9 C x= +/- 3 √3 D x= +/- 9 √2 FIRST TO ANSWER CORRECTLY GETS BRAINLIEST :

-)

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

The answer is C.

Step-by-step explanation:

You have to square both sides :

${x}^{2} = 27$

$x = ± \sqrt{27}$

Then, you have to simplify it :

$x = ± \sqrt{9 \times 3}$

$x = ±( \sqrt{9} \times \sqrt{3} )$

$x = ±( 3 \times \sqrt{3} )$

$x = ±3 \sqrt{3}$

GarryVolchara [31]3 years ago

7 0

Answer:

Option C) x = ± $3\sqrt{3}$

Step-by-step explanation:

=> $x^2 = 27$

Taking sqrt on both sides

=> x = ± $\sqrt{27}$

=> x = ± $\sqrt{3 * 3*3}$

=> x = ± $3\sqrt{3}$

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Answer:

Step-by-step explanation:

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Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

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Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

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$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

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denis-greek [22]

Answer:

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