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Vilka [71]
3 years ago
15

What lies between 1 by 2 and 2 by 3a) 1 by 2b) 4 by 5c) 5 by 6d) ​

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

I think the answer would be A .

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Which ordered pair in the form (x, y) is a solution of this equation?
laiz [17]

Answer:

Substitute the x and y values from the ordered pairs into the equation, one by one, until both sides of the equation are equal.

Step-by-step explanation:

A. (-2,-3)

3 * (-2) - 4 * (-3) = 21

-6 + 12 = 21

6 = 21 <u>not equal</u>

B. (0,7)

3 * 0 - 4 * 7 = 21

0 - 28 = 21

- 28 = 21 <u>n</u><u>o</u><u>t</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u>

C. (7,0)

3 * 7 - 4 * 0 = 21

21 - 0 = 21

21 = 21 <u>equal</u>

6 0
2 years ago
What is .22 divided by 88.66​
Nana76 [90]

Answer:

0.00248139

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2-2x2-(39 divided by 1)+2+9
artcher [175]
-30 is the answer for your question
6 0
3 years ago
5+8^-38 what is the answer please
Eddi Din [679]
Well if the 8 is squared the answer should be 31
3 0
3 years ago
PLS HELP!! AND HURRY!! Find an expression for the nth term ( tn ) in each of the following sequences:
fiasKO [112]

If the pattern continues, so that each term is separated by a distance of 3, then the sequence is given by the recursive rule

\begin{cases}a_1=1\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}

From this definition, we can write a_n in terms of a_1:

a_2=a_1+3

a_3=a_2+3=(a_1+3)+3=a_1+2\cdot3

a_4=a_3+3=(a_1+2\cdot3)+3=a_1+3\cdot3

a_5=a_4+3=(a_1+3\cdot3)+3=a_1+4\cdot3

and so on, up to

a_n=a_1+(n-1)\cdot3

(notice how the subscript on <em>a</em> and coefficient on 3 add up to <em>n</em>)

or

a_n=1+3(n-1)=3n-2

6 0
3 years ago
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