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nadezda [96]
3 years ago
11

Help me with this problem that I'm stuck on!

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0
                              4/(x+1) = 3/x + 1/15
Should we make common denominators with everything, we get
           4*15*x / [15x(x+1)] = 3*15*(x+1)/[15x(x+1)] + x(x+1)/[15x(x+1)]
Multiply both sides of the equation by the denominator to cancel them
                                         60x = 45(x+1) + x(x+1)
                                         60x = 45x + 45 + x^2 + x
                       x^2 - 14x + 45 = 0
                               (x-9)(x-5)  = 0
The answer to this question is that the solutions are x=9 and x=5.
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Answer:

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Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

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To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

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So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

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