To find the equation of the straight line equation i.e, we must be given with the two points $\left (x_{1},y_{1} \right )$ and $\left (x_{2},y_{2}\right )$

Since from the graph the two points closest to the line are $\left ( 10,36 \right )$ and $\left ( 22,12 \right ).$

Equation of line with two points closest to the line :

$y-y_{1}=m\cdot \left ( x-x_{1} \right )$

where m is the slope.

First we find the slope(m)= $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{12-36}{22-10}$

on simplify we get, $m=-2$ .

Now, to find the equation of the line: $y-y_{1}=m\cdot \left ( x-x_{1} \right )$

$y-36=\left ( -2 \right )\cdot \left ( x-10 \right )$

Apply distributive property on right hand side, we get

$y-36=-2\cdot x+20$

Adding both sides by 36, we get

$y=-2x+20+36$

$y=-2x+56$ .

The equation for the linear model in the scatter plot obtained by the two closest point $\left ( 10,36 \right ) and \left ( 22,12 \right )$ closest to the line is,

$y=-2x+56$

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