Answer:
range {3, 5, 6, 7 }
Step-by-step explanation:
to find the range substitute each value of x from the domain into f(x)
f(- 3) = -(- 3) + 4 = 3 + 4 = 7
f(- 2) = - (- 2 + 4 = 2 + 4 = 6
f(- 1) = - (- 1) + 4 = 1 + 4 = 5
f(1) = - 1 + 4 = 3
range y ∈ { 3, 5, 6, 7 }
So walked 4/5 mile in a 4/9 h so just use the rule of 3 simple
60 minutes ------ 1 hour
x min. ----------- 4/9 h
--------------------------------
x = 4/9 *60/1 = 240/9 = 26,6 min.
4/5 mile -------in 26,6 min.
1 mile -------- x min.
-----------------------------
x = 1*26,6/(4/5) = 26,6 /(0,8) = 33,25 min.
1 mile ..... 33,25 min.
x miles ----- 60 min.
---------------------------
x = 60/33,25 = 1,8 miles
so their unit rate in miles per hour will be 1,8 miles / hour
hope this will help you.
Answer:
1/4
Step-by-step explanation:
To transform PQR into P'Q'R, dilate the preimage by 1/4, or shrink it by a scale factor of 4 because 3/12 = 1/4
The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.
<h3>What is
speed?</h3>
The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula
A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.
A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.
This train does not make any stops.
Let the speed of both trains be equal.
Then the time taken by the first train will be
t₁ = 3:05 p.m. - 1:25 p.m.
t₁ = 1 hour 40 minutes
Then the time taken by the second train will be
t₂ = 1:40 - 00:15
t₂ = 1:25 = 1 hour 25 minutes
The time when the second train is at Niles junction will be
→ 4:30 p.m. + 1:25
→ 5:55 p.m.
More about the speed link is given below.
brainly.com/question/7359669
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To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
