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nydimaria [60]
2 years ago
15

4 4/5 x 3 2/6 I don’t understand this pls help

Mathematics
2 answers:
wolverine [178]2 years ago
5 0

Answer:

= 46 14/15

Step-by-step explanation:

Find the greatest common factor of the numerator and denominator:Factor out and cancel the greatest common factor:Multiply the fractions:Simplify the arithmetic:Simplify the arithmetic
Hope You Enjoy !

klasskru [66]2 years ago
4 0

Answer:

change to improper fraction

24/5 × 20/6=16 (you cross multiply)

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Area models 6437 divide 5
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Answer:

1,287.4

Step-by-step explanation:

6,437/5=1,287.4

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3 years ago
Graph the solution on the number line 3x + 3) - 244 or 1-**-1<br> I need answer
viva [34]
Okay so 3x + 3 - 244 = -238 so I think you would put -238 on the number line and then fill in the line to the negative spot I hope that helps
3 0
3 years ago
Order the following numbers from least to greatest 1.9, 1 1/3, 2, 0.5
masya89 [10]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938&#10;

Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
Need help figuring out this problem!
JulijaS [17]
6[13-2(4+1)]

Solve what is in the bracket first.
Parenthesis first.

6[13-8-2]
6(3)
18


7 0
3 years ago
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