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nydimaria [60]
3 years ago
15

4 4/5 x 3 2/6 I don’t understand this pls help

Mathematics
2 answers:
wolverine [178]3 years ago
5 0

Answer:

= 46 14/15

Step-by-step explanation:

Find the greatest common factor of the numerator and denominator:Factor out and cancel the greatest common factor:Multiply the fractions:Simplify the arithmetic:Simplify the arithmetic
Hope You Enjoy !

klasskru [66]3 years ago
4 0

Answer:

change to improper fraction

24/5 × 20/6=16 (you cross multiply)

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7cm each. reason: the rod of 21cm lenght will be cut into 3pieces of 7cm each, while that of 14cm will be cut into 2 pieces of 7cm each. Therefore, there 5 pieces of rods of 7cm each. Thanks.
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3 years ago
The distance in the x-coordinates from A(–2, 2) to the center of dilation F(1, 1) is unit(s).
lilavasa [31]

Answer:

The distance in the x-coordinates from A(–2, 2) to the center of dilation F(1, 1) is 3 unit(s)

Step-by-step explanation:

Give points:

A(-2,2)

Center of dilation F(1,1)

The distance in the x-coordinates fro A to F can be given by =\ |x_2-x_1\ |=\ |1-(-2)\ |=\ |1+2\ | = 3\ units.

5 0
3 years ago
What term describes this polygon ?
Alja [10]

Answer:

Step-by-step explanation:

The last one

I hope I helped you.

4 0
3 years ago
A pack of cinnamon-scented pencils sells for $6.00. What is the sales tax rate if the total cost of the pencils is $6.48?
snow_tiger [21]
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6 0
3 years ago
In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
kow [346]

Answer:

\cos(J) = 0.67

Step-by-step explanation:

Given

\angle K = 90^o

KJ = 65

IK = 72

JI = 97

Required

\cos(J)

The question is illustrated with the attached image.

From the image, we have:

\cos(J) = \frac{KJ}{JI}

This gives:

\cos(J) = \frac{65}{97}

\cos(J) = 0.67010309278

\cos(J) = 0.67 --- approximated

7 0
3 years ago
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