The measure of center and range to be used to compare the population is the median and the inter quartile range.
<u>Explanation:</u>
You utilize the median and the interquartile range (IQR) to portray skewed distributions of information. To look at two populaces, utilize the mean and the MAD when the two populations are symmetric. Utilize the middle and the IQR when possibly one or the two circulations are slanted.
In statistics and probability theory, the median is the worth isolating the higher half from the lower half of an information test, a populace or a likelihood circulation. For an informational collection, it might be thought of as the "center" esteem.
Factor x as it is a common factor;
x(8+3)
=11x
Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3
Answer:
- <u>3 </u><u>and</u><u> 17</u> are required integers
Step-by-step explanation:
- Let one integer be x
- And other integer be y
x = 4y + 5
xy = 51
<u>According to </u><u>question </u><u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u><u>x = 17</u>
∴ The required integers are <u>3 and 17</u>
Answer:
are this if its a function or not?
