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3 years ago

Can somebody help me out my mom won’t let me sleep until I do it

Mathematics

1 answer:

Galina-37 [17]3 years ago

4 0

Check the picture below.

$\bf \textit{arc's length for }\mathbb{ST}\\\\ s = \cfrac{\pi \theta r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ r= 4\\ \theta =60 \end{cases}\implies s = \cfrac{\pi (60)(4)}{180}\implies s = \cfrac{4\pi }{3}\implies s\approx 4.2 \\\\[-0.35em] ~\dotfill$

$\bf \textit{arc's length for }\mathbb{PT}\\\\ s = \cfrac{\pi \theta r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ r= 4\\ \theta =120 \end{cases}\implies s = \cfrac{\pi (120)(4)}{180}\implies s = \cfrac{8\pi }{3}\implies s \approx 8.4$

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mel-nik [20]

Answer:

61=x ( vertical opposite angle)

61=y (corresponding angle)

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3 years ago

PLEASE HELP, BEEN STUCK FOR AN HOUR

djverab [1.8K]

Answer:

Step-by-step explanation:

To sketch a quadratic function we need two things:

1) Nature of the curve

2) Vertex

3) y-intercept

The completing square form of the quadratic equation is:

$y=a(x-h)^2+k$

where,

a represents the nature of the graph it can be maximum or minimum , meaning, if a > 0 then minimum(u shaped curve/happy face) and if a < 0 then maximum(n shaped curve/sad face).

h represents the x-coordinate of the vertex.

k represents the y-coordinate of the vertex.

Now if we compare g(x) with our completing square form we get the following:

$g(x)=(x-4)^2+12\\y=a(x-h)^2+k\\$

When we simply compare the following we get ,

a = 1 , which means a > 0 since 1 is greater than 0 the nature of the curve will be minimum(happy face/u shaped)

h = 4, which means the x-coordinate of the vertex is 4

k = 12, which means the y-coordinate of the vertex is 12

Now we have the nature of the curve, we have the vertex now all we need is the y-intercept.

For y-intercept:

For y-intercept meaning at which point will the graph cross the y-axis(0 , y)

For that we expand the formula and turn it into the standard quadratic equation form by using the formula (a - b)^2

$y=(x-4)^2+12\\y=((x)^2-2(x)(4)+(4)^2)+12\\y=x^2-8x+16+12\\y=x^2-8x+28\\$

now we compare with the standard quadratic form:

$y=ax^2+bx+c$

here c is the y-intercept and while comparing we can see that c = 28 ,

so the curve cuts the y-axis at (0 , 28)

So we have all the three things that we need to graph our function.

So we just plot the y-intercept , the vertex , and join the dots. Just a tip draw a dotted line on the x-coordinate of the vertex because the vertex point is also called as a turning point where the graph goes in the opposite direction just like a mirror reflection. I attached 2 images you can check them out. One is handmade(i know i suck at drawing but still xD) , one is sketched by online graphing calculator.

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3 years ago

You charge customers $18.75 for lube service, parts, and labor. Assuming you take one hour's labor at $15, and the parts cost $3

hram777 [196]

Let
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we know that
$18.75=$15+$3.50+$T
T=18.75-15-3.5
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the answer is
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2 years ago

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kondaur [170]

Answer: