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alex41 [277]
3 years ago
10

Amanda wants to examine the eating habits of 100 random students at lunch to determine how many students eat in the cafeteria

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

well she can count up the average amount of tables, and the average amount of students in the school, later determine how many kids sit at the tables, for example, if there's five tables, and in each table there are five students, round those up and you have 25 students, only Amanda's answer would be much higher depending on the school and cafeteria

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In a random sample of 200 Americans, 51% said they favor building more nuclear power plants. In a random sample of 150 French, 4
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Answer:

Yes, there is enough evidence to say the proportions are the same.

Step-by-step explanation:

Null hypothesis: The proportions are the same.

Alternate hypothesis: The proportions are not the same.

Data given:

p1 = 51% = 0.51

n1 = 200

p2 = 48% = 0.48

n2 = 150

pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497

Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556

The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.

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