Example 1<span>
<span><span>verbose explicit high3 <span>plus </span>4 <span>cross </span>2 <span>minus </span><span>minus </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>1 3</span><span>verbose explicit high semantics3 <span>plus </span>4 <span>times </span>2 <span>minus </span><span>negative </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>13</span><span>verbose explicit high semantics high3 <span>plus </span>4 <span>times </span>2 <span>minus </span><span>negative </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>13</span></span>
</span>
For most fractions, the beginning is indicated with "start fraction", the horizontal line is indicated with "over", and the end of the fraction is indicated by "end fraction". For the semantic interpretation, most numeric fractions are spoken as they are in natural speech. Also if a number is followed by a numeric fraction, the word "and" is spoken in between.
Your answer is A.) for ur problem
Answer:
14 month
Step-by-step explanation:
Lets create equations for these two gyms. I believe this is an algebra 1 problem.
Community Gym: y=70x+50
Workout Gym: y=60x+190
Because both gyms are equal to y, we can set them together and solve for x.
70x+50=60x+190
10x=140
x=14
You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months
Therefore, after 14 months you will have paid the same amount for both gyms.
Discount =5%
Regular price =$83
Price at which daniel bought the shorts =$83-5%of$83
=$83-5×83/100
=$78.85
Answer:
11.33 * 16.33 meters to the nearest hundredth.
Step-by-step explanation:
Let the width of the pool be x meters, then the length is x+5 meters.
The length of whole area = x + 5 + 2(3) = x + 11 meters and the width is
x + 2(3) = x + 6 meters.
So we have the equation (x + 6)(x + 11) = 387.
x^2 + 17x + 66 = 387
x^2 + 17x - 321 = 0
x = [-17 +/- sqrt (17^2 - 4*1*-321)] / 2
x = 11.33 meters
So the width is 11.3 m and the length is 16.33 meters.
