The line that is perpendicular to the line on the graph is y=3
Answer:
The answer would be X=24
Step-by-step explanation:
Y is multiplied by 3 to get the answer 30. Because they are varied directly you have to multiply the 8 by 3 to get your answer!
-Hope this helps-
~Bai~
Answer:
m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 58° ; m ∠6 = 122°
Step-by-step explanation:
a ║ b
m∠2 = m∠6 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠7 = m∠3 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠2 = 3x + 20 Given
m∠7 = 2x - 10 Given
m∠6 + m∠3 = 180° If ║ cut by a transversal, then each pair of same-side
interior angles (also called consecutive interior angles
are supplementary (sum = 180°) .
3x + 20 + 2x - 10 = 180°
5x + 10 = 180°
5x = 170°
x = 34°
Answer: m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 2(34) - 10 ; m∠6 = 3(34) + 20
m∠3 = 58° ; m ∠6 = 122°
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
Answer:
57
Step-by-step explanation:
Subtract one player from the total number, because one has to block.
19
Multiply this by the number of goalies there are.
19*3=57
There will be 57 kicks.
