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jasenka [17]
4 years ago
10

(6 + 73)2

Mathematics
1 answer:
Molodets [167]4 years ago
6 0

Answer:45+1273

Step-by-step explanation:

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Find the volume of a sphere whose surface area is 1256 sq.cm (Take π = 3.14)<br>​
Alekssandra [29.7K]

Curved surface area of a sphere =1256 cm

2

We know that, Curved surface area of a spehre =4πr

2

⟹1256=4×3.14×r

2

⟹r

2

=

4×3.14

1256

⟹r

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∴r=10 cm

Hence, the answer is 10 cm.

4186.66666666 volume of sphere

6 0
3 years ago
Read 2 more answers
List the sides of triangle ΔMNP in ascending order (shortest to longest) if: Chapter Reference a m∠M = 64°, m∠N = 48°
scoray [572]
The given angles are 
M = 64
N = 48
where P is unknown. While we don't know P at first, we can solve for it. Recall that for any triangle, the three angles always add to 180 degrees

M+N+P = 180
64+48+P = 180
112+P = 180
112+P-112 = 180-112
P = 68

-------------------------------------------

So in summary so far
M = 64
N = 48
P = 68

The shortest side is opposite the smallest angle. The side MP is opposite the smallest angle N = 48

The longest side is going to be opposite the largest angle. In this case, side MN is opposite the largest angle P = 68

The medium side is opposite the medium angle. So NP is the medium side length

-------------------------------------------------------

Final Answers:
Shortest Side = MP
Medium Side = NP
Longest Side = MN
See the attached image for a visual summary

The ascending order would be: MP, NP, MN

Note: Something like MP is the same as PM. The order of endpoints for any given individual segment doesn't matter

6 0
3 years ago
Solve: 4|x| = 32 a 8 b –8 or 8 c 24 d No solution
anyanavicka [17]

x= -8 , 8

your answer

b –8 or 8

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Can you tell how many cubes are in the model?
Trava [24]
20 cubes are in the model


4 0
3 years ago
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1) 225<br> What is the square root of 225 simplified?
Goryan [66]

Answer: 15

Step-by-step explanation: This is one of those square roots you'll memorize really quickly. You don't even have to simplify it, since it's an integer.

7 0
3 years ago
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