Step-by-step explanation:
3.2÷0.88=3.636$
2.2÷1=2.2lbs
3.636/2.2lbs
1.652/1lbs
Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
Step-by-step explanation:
Area of a circle=πr²
A=π*4²
A=16π
A=50.27 ( rounded to nearest 100th)
Answer:
They earned $9.60 they will each get $4.80. Give or take.
Step-by-step explanation:
9.60÷2=4.80
Where are the answer choices lol
