1st serving: 2/3 * 1/2 = 2/6 or 1/3
2nd serving: 1/3 * 1/2 = 1/6
3rd serving: 1/6 * 1/2 = 1/12
4th serving: 1/12 * 1/2 = 1/24
5th serving: 1/24 * 1/2 = 1/48

1/3 + 1/6 + 1/12 + 1/24 + 1/48
1/3 * 16/16 = 16/48
1/6 * 8/8 = 8/48
1/12 * 4/4 = 4/48
1/24 * 2/2 = 2/48
1/48 * 1/1 = 1/48

16/48 + 8/48 + 4/48 + 2/48 + 1/48 = 31/48

Bobby ate 31/48 of the cake in total.

4 0

3 years ago

Which statement about AABC and ADEF is true? ^^^ A. B. C. D.

Katarina [22]

C is the correct answer! If it’s wrong I’m so sorry huh

5 0

3 years ago

Kim purchased 6 small containers of potato salad and Seth purchased 2 extra large containers of potato salad. What is the differ

icang [17]

I am assuming that the attached is the complete question and we need to get the information from the table.

From the table we know the below fact:

$1 \; small \; container \; of \; potato \; salad \; Weighs \; \frac{2}{8} \; pounds\\\\1 \; extra \; large \; container \; of \; potato \; salad \; Weighs \; \frac{9}{8} \; pounds$

$Weight \; of \; 6 \; small \; container = 6 \times \frac{2}{8} = \frac{12}{8} \; pounds\\\\Weight \; of \; 2 \; Extra \; large \; container = 2 \times \frac{9}{8} \; = \; \frac{18}{8} \; pounds$

Conclusion:

The difference in weights, in pounds of Kim’s and Seth’s purchases is given below:

$\frac{18}{8} - \frac{12}{8} = \frac{18-12}{8} = \frac{6}{8} \\\\Simplifying \; the \; fraction \; dividing \; by \; 2 \; on \; both \; numerator \; and \; denominator\\\\ \frac{6 \div 2}{8 \div 2} = \frac{3}{4}$